Answer:
The change in momentum experienced by the bowling ball is 96 kgm/s.
Explanation:
Given;
mass of the bowling ball, m = 12 kg
velocity of the bowling ball, v = 8 m/s
time of motion, t = 10 s
The change in momentum experienced by the bowling ball is equal to the impulse experienced by the bowling ball.
ΔP = J = F x t
Therefore, the change in momentum experienced by the bowling ball is 96 kgm/s.
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
