Hello
1) First of all, since we know the radius of the wire (

), we can calculate its cross-sectional area

2) Then, we can calculate the current density J inside the wire. Since we know the current,

, and the area calculated at the previous step, we have

3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity

of the aluminium, the electric field is given by
<span>"Does lack of sunlight affect plant growth?"
This question can be investigated with procedures according to
the Scientific Method, because "lack of sunlight" can be arranged
unambiguously, and "affected plant growth" can be identified
unambiguously.
The other questions involve words or phrases with ambiguous definitions,
that can mean different things to different people, and would be hard to
agree on, like "</span><span>best advice", "sound quality", and "happiness in life".</span>
Answer:

T=157.06 N
Explanation:
Given that
Mass of first block = 21.1 kg
Mass of second block = 12.9 kg
First mass is heavier than first that is why mass second first will go downward and mass second will go upward.
Given that pulley and string is mass less that is why both mass will have same acceleration.So lets take their acceleration is 'a'.
So now from force equation

21.1 x 9.81 - 12.9 x 9.81 =(21.1+12.9) a

Lets tension in string is T


T=21.1(9.81-2.36) N
T=157.06 N
The question is incomplete. Here is the complete question.
A floating ice block is pushed through a displacement vector d = (15m)i - (12m)j along a straight embankment by rushing water, which exerts a force vector F = (210N)i - (150N)j on the block. How much work does the force do on the block during displacement?
Answer: W = 4950J
Explanation: <u>Work</u> (W), in physics, is done when a force acts on an object that has a displacement form a place to another:
W = F · d
As the formula shows, Work is a scalar product, i.e, it results in a number, so, Work only has magnitude.
Force and displacement for the ice block are in 2 dimensions, then work will be:
W = (210)i - (150)j · (15)i - (12)j
W = (210*15) + (150*12)
W = 3150 + 1800
W = 4950J
During the displacement, the ice block has a work of 4950J
Answer:
Velocity,v = 0.323 m/s
Explanation:
The acceleration of a particle is given by :

b = 0.8 m when x = 0
Since,

![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D%2Bc)
At x = 0, v = 1 m/s


![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D-0.3)
At x = -1 m


v = 0.323 m/s
So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.