A car of mass 600 Kg is moving at 15m/s. Calculate its momentum.

What material would make the best light bulb filament?

DanielleElmas [232]

The answer is B ! As in light bulb tungsten is working as resistor !

7 0

3 years ago

Read 2 more answers

An object becomes positively charged when it

Montano1993 [528]

Answer:

D

Explanation:

8 0

3 years ago

parallel-plate capacitor is made of two square plates 25 cm on a side and 1.0 mmapart. The capacitor is connected to a 50.0-V ba

noname [10]

Answer:

6.9 x 10^-7 J

3.5 x 10^-7 J

Explanation:

Identify the unknown:

The energies stored in the capacitor before and after the plates are pulled farther apart

List the Knowns:

Voltage of the battery: V = 50 V

Area of the plates: A = 0.25 x 0.25 = 0.0625 m^2

Original distance between the plates: d = 1 mm = 10^-3 m

New distance between the plates: d = 2 mm = 2 x 10^-3 m

Permittivity of free space: ∈o = 8.85 x 10^-12 C^2/Nm^2-

Set Up the Problem:

Capacitance of a parallel-plate capacitor:

C=∈o*A/d

Energy stored in a capacitor:

U_c=(1/2)*V^2*C

Solve the Problem:

Before the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/10^-3 = 5•53 x 10^-10 F

U_c = (1/2) x (50)^2 x 5.53 x 10^-10= 6.9 x 10^-7 J

After the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/2*10^-3 = 2•77 x 10^-10 F

U_c = (1/2) x (50)^2 x 2•77 x 10^-10 = 3.5 x 10^-7 J

The energy decrease because the capacitance decrease, so the stored charge decrease and transferred to the battery

3 0

3 years ago

What processes were involved in the formation of the model? How is the model similar to the real sedimentary sample? How is the

Stels [109]

Answer:

1. sediment layering and compacting on top of each other and solidifying

2. sediment layering and compacting (not as much) on top of each other and solidifying, just not as much

Explanation:

hope this helps! :))

8 0

3 years ago

A 10.3 kg weather rocket generates a thrust of 240 N. The rocket, pointing upward, is clamped to the top of a vertical spring. T

jenyasd209 [6]

Answer:

(a) x = 0.25 m

(b) v = 1.46 m/s

(c) v = 2.4 m/s

Explanation:

mass (m) = 10.3 kg

force from thrust (F) = 240 N

spring constant (k) = 400 N/m

stretch distance from thrust (y) = 30 cm = 0.3 m

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) from mg = kx

compression (x) = mg/ k

x = $\frac{10.3 x 9.8}{400}$

x = 0.25 m

(B) from the conservation of forces

(Fy) + (0.5k $x^{2}$ ) = (0.5k $y^{2}$ ) + mgh + (0.5m $v^{2}$ )

v = $\sqrt{[tex]\frac{(Fy) + (0.5k[tex]x^{2}$ ) - (0.5k $y^{2}$ ) - mgh }{0.5m}[/tex]}[/tex]

v = $\sqrt{[tex]\frac{(240 x 0.3) + (0.5 x 400 x [tex]0.25^{2}$ ) - (0.5 x 400 x $0.3^{2}$ ) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]

v = 1.46 m/s

(C) if the rocket weren't attached to the spring, the conservation of energy equation becomes

(Fy) + (0.5k $x^{2}$ ) = mgh + (0.5m $v^{2}$ )

v = $\sqrt{[tex]\frac{(Fy) + (0.5k[tex]x^{2}$ ) - mgh }{0.5m}[/tex]}[/tex]

v = $\sqrt{[tex]\frac{(240 x 0.3) + (0.5 x 400 x [tex]0.25^{2}$ ) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]

v = 2.4 m/s

7 0

3 years ago