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erica [24]
2 years ago
15

A 2.00MeV neutron is emitted in a fission reactor. If it loses half its kinetic energy in each collision with a moderatoratom, h

ow many collisions does it undergo as it becomes a thermal neutron, with energy 0.039 eV ?
Physics
1 answer:
Aliun [14]2 years ago
7 0

A 2.00MeV neutron is emitted in a fission reactor. If it loses half its kinetic energy in each collision with a moderator atom, it will undergo 26 collisions as it becomes a thermal neutron, with energy 0.039 eV

How to find the number of collisions moderator atom will undergo?

After n\\ collisions, the kinetic energy of the neutron become :

E=\frac{Ei}{2^n}

where, E_i is the initial kinetic energy and n is the number of collisions.

We can rewrite the expression as:

2^n=\frac{E_i}{E}

Taking the natural log both sides, we get:

n=\frac{ln\frac{E_i}{E} }{2}

Now, from the given data, we have that E_i=2MeV and E=0.039eV.

Substituting the values and solving, we get

n=\frac{ln\frac{2\times 10^6}{0.039} }{ln2} =26

Hence, the number of collisions are 26.

To learn more about fission reactor, refer to:

brainly.com/question/23276812

#SPJ4

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