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Orlov [11]
3 years ago
6

What is x? 4x+10=-26 A.-4 B-9 C. 9

Mathematics
2 answers:
WITCHER [35]3 years ago
6 0
X is 9 or c because -26-10 is -36 and -36/-4 is 9
lions [1.4K]3 years ago
5 0
4x + 10 = -26
-10 both sides
4x = -26 -10
4x = -36

4x/4 = -36/4

x = -9
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3 years ago
Which of the pairs (2, 3), (1, 2.5), (6, 1), or (−2, 2) is the solution to the equation 4y−x= 10?
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6 0
3 years ago
Hi :) how to do question 7 ?
Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

  • We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= \frac{-3}{2}x+8  
  • We khow that the points P and Q are two points in the cercle
  • Let Ω be the center of this cercle
  • we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
  • So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
  • Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
  • PΩ=\sqrt{(a-4)^{2}+(b-6)^{2}  } and QΩ=\sqrt{(a-8)^{2}+(b-2)^{2}   }
  • Let's substitute a by x and b by y
  • PΩ=QΩ we substitute each distance by its expression
  • After simplyfying the expressions we get finally : -12+8x-8y=0
  • now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
  • these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
  • we substitute a by 4 and y by 2 in PΩ to get the radius
  • we get r = \sqrt{(4-4)^{2}+(2-6)^{2}  } = 4
  • so r²= 16
  • then the equation is : (x-4)²+(y-2)²=16
5 0
3 years ago
Read 2 more answers
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