Pull into the lot of a place that's 24 hours therefor if a office drives by its just a car
Answer:
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Explanation:
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Answer:
Displacement by cyclist is zero.
Explanation:
In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.
The bicyclist starts from P and travel through Q and R and returned to P again.
We need to find its displacement.
We know displacement of a body is its difference between its initial position to final position.
Here in the given question the bicyclist returns to P again.
Therefore, total displacement by bicyclist is zero.
Hence, this is the required solution.
Answer:
Explanation:
The speed of the astronaut can be found with the help of law of conservation of momentum .
mv = MV , M is mass of astronaut , m is mass of object thrown , v is velocity of object thrown and V is velocity of astronaut.
Putting the values
77.5 x V = .94 x 12
V = .14554 m /s
This will be the uniform velocity of astronaut.
Distance to be covered = 37.3 m
time taken = distance / velocity
= 37.3 / .14554
= 256.28 s
= 4.27 minutes.
Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
