A horizontal force of 675 N is needed to overcome the force of static friction between a level floor and a 300-kg crate. What is
the acceleration of the crate if the 675-N force is maintained after the crate begins to move and the coefficient of kinetic friction is 0.15
1 answer:
Explanation:
Below is an attachment containing the solution.
You might be interested in
Explanation:
Let acceleration due to Gravity for a planet is given by:

Here,
Escape velocity is given by:

Here,
and g_X = 2g
Therefore,
To keep the energy going every day
B
M
‘’’’
Vujkbukbuvuvubkkbbiu
Work done is the distance a force acts over.
So, the work done here is 9.0N * 3.0m = 27 J
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.