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svetlana [45]
4 years ago
9

if (-4,5) is the only solution to a system of two linear equations, then the graphical solution would show:

Mathematics
1 answer:
egoroff_w [7]4 years ago
7 0
What shape do <em>linear <u /></em><u />equations make? To picture the solution visually, you can imagine two of those shapes meeting on a graph at one (and only one) point, (-4,5).
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Tasha purchased a $40 shirt on sale for $30 how much of a discount did Tasha recieve
WITCHER [35]
She received $10 discount
6 0
3 years ago
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Use the function f(x) = 2 - 5x to fill in the blanks in the table. x f(x)
kvasek [131]
I will one only and you do the rest.

Let x = -2

Plug into given function.

f(-2) = 2 - 5(-2)

f(-2) = 2 + 10

f(-2) = 12

So, when x = -2, f(x) = 12.

Table:

x............ f(x)
-2 12
-1
0
1
2

Find the rest the same way.



5 0
3 years ago
Rebecca answered 42 of 60 questions correctly on a test which method should he she used to find the percent of question she answ
MakcuM [25]

She answered 70% questions correctly

Further explanation:

Percetages are used to calculae the success or failure in tests or exams usually.

Given

Total\ questions= 60\\The\ questions\ attempted\ correctly=42

The percentage will be calculated as follows:

Percentage\ of\ correctly\ answered\ questions=\frac{Correct\ questions}{Total\ questions}*100\\= \frac{42}{60}*100\\=70\%

She answered 70% questions correctly

Keywords: Percentage, Success rate

Learn more about percentage at:

  • brainly.com/question/9532142
  • brainly.com/question/9590016

#LearnwithBrainly

3 0
3 years ago
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Could someone help me please???​
mylen [45]

3 hours worked - $19.50

0.5 hours - x

x= 0.5(19.5)/3

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and then do the same for the other cases

6 0
4 years ago
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a previous analysis of paper boxes showed that the standard deviation of the length is 9mm. What is the 98% confidence interval
il63 [147K]
We cannot calculate the confidence interval without the sample size.  However, for the second question, the sample size needed would be 49.

The formula we use is

n=(\frac{z_{\frac{\alpha}{2}}\times \sigma}{E})^2

To find the z-score:
Convert 98% to a decimal:  0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is closest to a z-score of 2.33.

Using the z-score, our standard deviation (9) and our margin of error (3), we have:
n=(\frac{2.33(9)}{3})^2=(6.99)^2=48.86\approx 49
6 0
3 years ago
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