Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a =
a=
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity .
The cross-sectional area of the of a wire is given by;
where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;
Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;
Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;
Given;
We then use equation (1) to fine the ratio of the area to
bearing in mind that
This ratio gives 0.8281. Substituting this into equation (5), we get the following;
Answer:
Speed of the point = 1.541 × 10⁶ m/h = 428 m/s
Explanation:
Modelling the earth as a sphere,
The equator and the pole have a length of an arc that's fully 90° of the whole 360° circular circumference.
A point located 1/4 of the length of the arc between the equator and the pole has an angle (1/4) × 90° arc = 22.5°.
On the attached image, θ = 22.5°, so Φ = 90° - 22.5° = 67.5°
To obtain the radius of the point on the globe
From the image again, it shows that trigonometric relations can be used to obtain this radius
Sin Φ = (radius of the point)/(radius of the earth)
Sin 67.5 = radius of the point/(6.37 × 10⁶)
Radius of the point = 6.37 × 10⁶ × 0.9239 = 5.885 × 10⁶ m
Speed of the point on the globe = (circumference of the circular path mapped out by the point during rotation)/(24 hours)
circumference of the circular path mapped out by the point during rotation = 2πr = 2π × 5.885 × 10⁶ = 3.6977 × 10⁷ m
Speed of the point = 3.6977 × 10⁷/24 = 1.541 × 10⁶ m/h = 428 m/s
