Does the image above correctly illustrate how the coriolis effect impacts global winds?

What is a science term for trapping heat?

expeople1 [14]

Insulation or insulating. :) Hope that helps!

4 0

4 years ago

A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t

enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

$v_{avg} = \frac{6000}{20*60}$

$v_{avg} = 5m/s$

now since effect of wind is in opposite direction then we can say

$V_{net} = v_{bird} - v_{wind}$

$5 = 9 - v_{wind}$

$v_{wind}= 4 m/s$

Part b)

now if bird travels in the same direction of wind then we will have

$v_{net}= v_{bird} + v_{wind}$

$v_{net} = 9 + 4 = 13 m/s$

now we can find the time to go back

$time = \frac{distance}{speed}$

$time = \frac{6000}{13}$

$time = 7.7 minutes$

Part c)

Total time of round trip when wind is present

$T = t_1 + t_2$

$T = 20 + 7.7 = 27.7 min$

now when there is no wind total time is given by

$T = \frac{6000}{9} + \frac{6000}{9}$

$T = 22.22 min$

So due to wind time will be more

4 0

4 years ago

Which of the following accurately describes the way in which a muscle moves?

Vaselesa [24]

<h3>Answer;</h3>

B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.

<h3>Explanation;</h3>

The events of muscle fiber shortening occurs with in the sacromeres in the fibers.
Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.
Filament movement starts at the region or zone where thin and thick filaments overlap.
Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.

7 0

3 years ago

If two firecrackers produce a sound level of 81 dBdB when fired simultaneously at a certain place, what will be the sound level

Mrac [35]

Answer:

77.96dB

Explanation:

Recall that decibels are a unit of measuring intensity of sound, and depend on the logarithm of the intensity

the intensity, measured in decibels is given by:

I(db)=10log(I/I0)

I is the intensity in MKS units; I0 is the threshold intensity for human hearing (10^-12 W/m^2)

Thus, if the two sounds together have a dB of 81, we know:

81=10log(I/I0)

using the data above, we can find the intensity of the two sounds to be

0.000125 W/m^2

therefore, one firecracker has an intensity half of that, or 0.0000625W/m^2

now use this value to find the dB of one firecracker:

I(dB0=10log(0.0000625/10^-12)=77.96dB

5 0

3 years ago

I need help on my physics work and show me how you got it please

algol13

Answer

It increases to B, then it decreases.

When the stone thrown upwards, it moves vertically upwards to a maximum height then is starts to come down. Due to gravitational force, the velocity of the stone projected upwards decreases but when coming down wards is increases.

The trajectory shown in the diagrams represents an example of an object projected upwards.

We can then says that the vertical component increases from A to B, then it decreases to C.

4 0

4 years ago