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Shalnov [3]
3 years ago
14

The angle of incidence at a solid/liquid boundary is 59.6a?°, and the index of refraction of the solid is n = 1.55. (a what must

be the index of refraction of the liquid such that the direction of the light entering the liquid is not changed? (b what is the largest index of refraction that the liquid can have, such that none of the light is transmitted into the liquid and all of it is reflected back into the solid?
Physics
1 answer:
Sergio039 [100]3 years ago
8 0

sorry I need coins to ask questions!


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A rock climber stands on top of a 50 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s a
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<h2><em>Answer: b) What was the initial speed of the second stone?</em></h2>

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3 years ago
The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e
Maksim231197 [3]

Answer:

\fbox{strength  \: of \:  the \:  other \:  charge  =  - 0.0196 Ke \: Coulomb}

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

|F| =  K_e \frac{q1 \cdot \: q2}{ {r}^{2} }  \\ 900 =K_e  \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times  {10}^{ - 4}  =  K_e {(2e - 10)\cdot \: q2} \\ q2 =   \frac{9 \times  {10}^{ - 2} }{(2e - 10) K_e}  \\  \\  \fbox{We \:  know \:  that \:  e = 2.71 } \\  substituting \: the \: value \: \\ q2 =  \frac{9 \times  {10}^{ - 2} }{(2 \times 2.71 - 10)K_e}  \\ q2 =  \frac{0.09}{ - 4.58 K_e}  \\ q2 =  \frac{-0.0196}{K_e}\: coulomb

\fbox{strength  \: of \:  the \:  other \:  charge  =  - 0.0196 Ke \: Coulomb}

<em><u>Thanks for joining brainly community!</u></em>

3 0
2 years ago
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