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ratelena [41]
2 years ago
10

What is the frequency, in units of kiloHertz, of an AC waveform that has a period of 12 microseconds?

Physics
1 answer:
Alik [6]2 years ago
3 0

Answer:

83.3 kHz

Explanation:

The frequency of a waveform is equal to the reciprocal of its period:

f=\frac{1}{T}

where

f is the frequency

T is the period

In this problem, we have

T=12 \mu s=12\cdot 10^{-6} s

so, the frequency of the waveform is

f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz

And by converting into kiloHertz,

f=8.33\cdot 10^4 Hz=83.3 kHz

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Alice drops a rock to a well. She hears the splash of the rock 4.1s later. The speed of sound is 340m/s. How deep is the well
Maksim231197 [3]

Answer:

697 m

Explanation:

From the question above,

Note: Alice hears the splash of the rock in the well through the help of echo.

Applying,

v = 2x/t........................ Equation 1

Where v = speed of sound, x = depth of the well, t = time.

make x the subject of the formula in equation 1

x = vt/2................... Equation 2.

Given: v = 340 m/s, t = 4.1 s

Substitute these values into equation 2

x = 340(4.1)/2

x = 697 m.

3 0
3 years ago
An athletes heart beats 62 times per minute. What is the frequency of her heart beat?
PilotLPTM [1.2K]

Answer:

22

Explanation:

bc it just is

8 0
2 years ago
How is matter changed from one state of matter to another? *
Digiron [165]

Explanation:

Matter is changed from one state to another by addition or removal of heat and suitable pressure conditions.

When a solid is heated, it normally melts and changes to liquids which on heating changes to vapor. The randomness of the particles increases from solid to liquid state and to gaseous states.

Also, a gas can be cooled to liquid and on further cooling transformed into a solid matter.

These phase changes are brought about by energy changes in a system. Some form of matter can also sublime by changing form solid to gas and vice versa.

4 0
3 years ago
A 1.1-kg object is suspended from a vertical spring whose spring constant is 120 N/m. (a) Find the amount by which the spring is
andriy [413]

Answer:

e = 0.0898m

v = 2.07m/s

Explanation:

a) According to Hooke's law

F = ke

e is the extension

k is the spring constant

Since F = mg

mg = ke

e = mg/k

Substitute the given value

e = 1.1(9.8)/120

e = 10.78/120

e = 0.0898m

Hence it is stretched by 0.0898m from its unstrained length

2) Total Energy = PE+KE+Elastic potential

Total Energy = mgh +1/2mv²+1/2ke²

Substitute the given value

5.0= 1.1(9.8)(0.2)+1/2(1.1)v²+1/2(120)(0.0898)²

Solve for v

5.0 = 2.156+0.55v²+0.48338

5.0-2.156-0.48338= 0.55v²

2.36 =0.55v²

v² = 2.36/0.55

v² = 4.29

v ,= √4.29

v = 2.07m/s

Hence the required velocity is 9.28m/s

4 0
3 years ago
Can someone please give me the answers to this? ... please ...
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