Um honestly I’m not sure but I need points but good luck god be with you mate
<span>tension, compression, and shearing and can i get brainliest plz</span>
Answer:
S= 1.40x10⁻⁵mol/L
Explanation:
The Henry's Law is given by the next expression:
(1)
<em>where S: is the solubility or concentration of Ar in water,
: is Henry's law constant and p: is the pressure of the Ar </em>
<u>Since the argon is 0.93%, we need to multiply the equation (1) by this percent:</u>
Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.
Have a nice day!
Answer:
v₁ = 37.5 cm / s
Explanation:
For this exercise we can use that angular and linear velocity are related
v = w r
in the case of the spool the angular velocity for the whole system is constant,
They indicate the linear velocity v₀ = 25.0 cm / s for a radius of r₀ = 1.00 cm,
w = v₀ /r₀
for the outside of the spool r₁ = 1.5 cm
w = v₁ / r₁1
since the angular velocity is the same we set the two expressions equal
v1 =
let's calculate
v₁ =
v₁ = 37.5 cm / s
Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>
Answer:
The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.
Explanation:
Let us call the mass of the balloon
and the mass of the basket
, then according to newton's second law:
,
where
is the upward acceleration, and
is the net propelling force (counts the gravitational force).
Also, the tension
in the rope is 79.8 N more than the basket's weight; therefore,

and this tension must equal


Combining equations (2) and (3) we get:

since
, we have

Putting this into equation (1) and substituting the numerical values of
and
, we get:


Thus, the mass of the balloon and the basket is 2295 kg and 301 kg respectively.