Your average speed was
(100 m) / (13.8 s) = 7.25 m/s .
If you finished 0.001s ahead of him, then at your average speed, that corresponds to
(7.25 m/s) x (0.001 s) = 0.00725 m
That's 7.25 millimeters ... about 0.28 of an inch !
NOTE:. I think this is only valid if your speed was a constant ~7.25 m/s all the way.
Answer:
15.66 rad/s
Explanation:
The vertical motion and horizontal motion are independent of each other.
t = √ ( 2 s/ g) where t = time for the ball to reach the ground and s is the height of the cliff = 18.0 m
t = √ ( 36 / 9.81 ) = 1.916 secs
horizontal distance travel = ut where u is the horizontal velocity of the stone = 30 × r (radius)
tangential velocity V = angular velocity ( ω) × radius
distance traveled = ω × r × t = 30 × r
radius cancelled on both side
ω = 30 / 1.9156 = 15.66 rad/s
Altitude is the angle measured above the horizon
Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F =
q =
we calculate
q =
q =
Ra 7 10-12
q = 2.65 10⁻⁶ C
Explanation:
According to Newton's second law of motion, the rate of change of momentum is directly proportional to the applied unbalanced force. The mathematical expression is given by:
![F=\dfrac{d(mv)}{dt}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bd%28mv%29%7D%7Bdt%7D)
Where
F is the applied force
m is the mass of the object
v is the velocity with which it is moving
![F=m\dfrac{dv}{dt}](https://tex.z-dn.net/?f=F%3Dm%5Cdfrac%7Bdv%7D%7Bdt%7D)
Momentum of a particle is given by the product of mass and velocity as :
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
Hence, this is the required solution.