Answer:
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Explanation:
A vehicle crash problem must be solved with the equation of the moment,
Initial instant Before crash
p₀ = m v₁ + mv₂
After the crash
= m 
+ m 
p₀ =
If the speed ratio before and after the crash is one
p₀ / = 1
We can assume that initially one of the cars was stopped
m v₁₀ = m
v₁₀ =
For the two speeds to be equal, the masses of the vehicles must be the same.
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Then the the speed of the molecules also increase
Answer:
(A). The rotational momentum of the flywheel is 12.96 kg m²/s.
(B). The rotational speed of sphere is 400 rad/s.
Explanation:
Given that,
Mass of disk = 10 kg
Radius = 9.0 cm
Rotational speed = 320 m/s
(A). We need to calculate the rotational momentum of the flywheel.
Using formula of momentum
Put the value into the formula
(B). Rotation momentum of sphere is same rotational momentum of the flywheel
We need to calculate the magnitude of the rotational speed of sphere
Using formula of rotational momentum
Put the value into the formula
Hence, (A). The rotational momentum of the flywheel is 12.96 kg m²/s.
(B). The rotational speed of sphere is 400 rad/s.
Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
