Not sure I understand can you explain more
Power = Work done / Time taken.
Work done = mgh
Mass, m = 33kg ( Am presuming it is 33 kg).
h = 85 m.
Work done = 33 * 9.81* 85 = 27517.05 J.
Time taken.
Since object was dropped from height, it fell under gravity.
Using H = ut + (1/2) * gt^2. u = 0.
H = 1/2 gt^2.
t = (2H/g) ^ (1/2)
t = (2*85/9.81) ^ 0.5 = 4.1628 s.
Power = 27517.05 / 4.1628 = 6610.23 Watts.
= 6610 W to 3 S. f.
Answer:
The combined speed of camper and canoe is 1.71 m/s.
Explanation:
Given that,
Mass of camper 1, m = 100 kg
Speed of camper 1, v = 3 m/s
The combined mass of another camper and canoe is, M = 175 kg
We need to find the combined speed of camper and canoe. According to the conservation of linear momentum, the momentum of first camper is equal to linear momentum of the canoe and the second camper.

So, the combined speed of camper and canoe is 1.71 m/s.
Answer:
it simply means KINETIC ENERGY
Explanation:
In physics, the kinetic energy (KE) of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes
<h3><u>Answer;</u></h3>
- In a freshwater lake
- In the atmosphere
- In Earth's mantle
<h3><u>Explanation</u>;</h3>
- <em><u>Convection currents are types that cause the process of convection, which the transfer of heat energy that occurs in fluids.</u></em>
- <em><u>Convection currents are circular patterns that occurs in fluids such that the less dense warm fluids rises up while denser cold fluids sinks, </u></em>it is this movement of less dense warm fluid and denser cold fluids that creates circular patterns that causes the process of convection to take place.
- <em><u>Convection currents may occur in the atmosphere where warm air rises while cold denser air sinks or moves towards the bottom, it may also occur in the mantle of the Earth and water or water bodies such as lakes.</u></em>