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Vlad1618 [11]
3 years ago
7

Solve the equation x=3logy2 for y.

Physics
2 answers:
qwelly [4]3 years ago
8 0
ANSWER
y =  {10}^{ \frac{x}{6} }


EXPLANATION

The logarithmic equation given to us is

x = 3 log( {y}^{2} )


Recall this property of logarithms,


log( {a}^{n} )  = n log(a)




We apply this property to the right hand side to obtain,



x =2 \times  3 log( {y} )


This implies that,

x =6 log( {y} )

We now divide both sides by 6 to get,


\frac{x}{6} =log( {y} )

We now take antilogarithm to get,


{10}^{ \frac{x}{6} }  = y


melisa1 [442]3 years ago
6 0

X = 3 · log(Y²)

X = 3 · 2·log(Y)

X/6 = log(Y)

10^(X/6) = 10^log(Y)

Y = 10^(X/6)

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FrozenT [24]

\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}

<h3><u>Provided</u><u>:</u><u>-</u></h3>
  • Initial velocity = 15 m/s
  • Final velocity = 10 m/s
  • Time taken = 2 s

<h3><u>To FinD:-</u></h3>
  • Accleration of the particle....?

<h3><u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>

We will solve the above Question by using equations of motion that are:-

  • v = u + at
  • s = ut + 1/2 at²
  • v² = u² + 2as

Here,

  • v = Final velocity
  • u = Initial velocity
  • a = acceleration
  • t = time taken
  • s = distance travelled

<h3><u>Work</u><u> </u><u>out</u><u>:</u></h3>

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
4 years ago
A boat that has a speed of 6km / h must cross a 200m wide river perpendicular to the current that carries a speed of 1m / s. Cal
ivanzaharov [21]

Answer:

a) 1.94 m/s

b) 120 m

Explanation:

Convert km/h to m/s:

6 km/h = 1.67 m/s

a) The final speed is found with Pythagorean theorem:

v = √((1.67 m/s)² + (1 m/s)²)

v = 1.94 m/s

b) The time it takes the boat to cross the river is:

t = (200 m) / (1.67 m/s)

t = 120 s

The displacement in the direction of the current is:

x = (1 m/s) (120 s)

x = 120 m

3 0
3 years ago
During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain
Cerrena [4.2K]

Answer:

Explanation:

Given that

Total race distance is 400m

Her initial velocity was 0m/s²

At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²

Using equation of motion

Let determine her constant acceleration

v²=u²+2as

12²=0²+2×a×100

144=0+200a

144=200a

a=144/200

a=0.72m/s²

Then we want to know her position after another 10second

So total time is 10+12=22seconds

Then, using equation of motion

Let determine his postion

S=ut+½at²

S=0•t+½×0.72×22²

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7 0
4 years ago
Read 2 more answers
A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t
aleksandr82 [10.1K]

Answer:

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Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

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u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

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Vlad1618 [11]

Actual velocity of the ping-pong ball= 5 m/s

Explanation:

velocity of ping pong ball because of the shot gun= 4 m/s North

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V= √25

V= 5 m/s

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4 years ago
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