
<h3>
<u>Provided</u><u>:</u><u>-</u></h3>
- Initial velocity = 15 m/s
- Final velocity = 10 m/s
- Time taken = 2 s
<h3><u>To FinD:-</u></h3>
- Accleration of the particle....?
<h3>
<u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>
We will solve the above Question by using equations of motion that are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
Here,
- v = Final velocity
- u = Initial velocity
- a = acceleration
- t = time taken
- s = distance travelled
<h3>
<u>Work</u><u> </u><u>out</u><u>:</u></h3>
By using first equation of motion,
⇛ v = u + at
⇛ 10 = 15 + a(2)
⇛ -5 = 2a
Flipping it,
⇛ 2a = -5
⇛ a = -2.5 m/s² [ANSWER]
❍ Acclearation is negative because final velocity is less than Initial velocity.
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer:
a) 1.94 m/s
b) 120 m
Explanation:
Convert km/h to m/s:
6 km/h = 1.67 m/s
a) The final speed is found with Pythagorean theorem:
v = √((1.67 m/s)² + (1 m/s)²)
v = 1.94 m/s
b) The time it takes the boat to cross the river is:
t = (200 m) / (1.67 m/s)
t = 120 s
The displacement in the direction of the current is:
x = (1 m/s) (120 s)
x = 120 m
Answer:
Explanation:
Given that
Total race distance is 400m
Her initial velocity was 0m/s²
At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²
Using equation of motion
Let determine her constant acceleration
v²=u²+2as
12²=0²+2×a×100
144=0+200a
144=200a
a=144/200
a=0.72m/s²
Then we want to know her position after another 10second
So total time is 10+12=22seconds
Then, using equation of motion
Let determine his postion
S=ut+½at²
S=0•t+½×0.72×22²
S=0+174.24
S=174.24 m
Her position will be 174.24m
Answer:
Acceleration: 
Explanation:
The acceleration of an object is equal to the rate of change of velocity:

where
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
For the space probe in this problem, we have:
u = 100 ft/s (initial velocity)
v = 5000 ft/s (final velocity)
t = 0.5 s (time taken)
Therefore, the acceleration is

Actual velocity of the ping-pong ball= 5 m/s
Explanation:
velocity of ping pong ball because of the shot gun= 4 m/s North
velocity added to the ping-pong ball due to the wind=3 m/s
These velocities are perpendicular to each other. so we use Pythagoras theorem to find the resultant velocity of the ping- pong ball
so the actual velocity of the ping-pong ball =V= √4²+3²
V= √25
V= 5 m/s