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Vlad1618 [11]
3 years ago
7

Solve the equation x=3logy2 for y.

Physics
2 answers:
qwelly [4]3 years ago
8 0
ANSWER
y =  {10}^{ \frac{x}{6} }


EXPLANATION

The logarithmic equation given to us is

x = 3 log( {y}^{2} )


Recall this property of logarithms,


log( {a}^{n} )  = n log(a)




We apply this property to the right hand side to obtain,



x =2 \times  3 log( {y} )


This implies that,

x =6 log( {y} )

We now divide both sides by 6 to get,


\frac{x}{6} =log( {y} )

We now take antilogarithm to get,


{10}^{ \frac{x}{6} }  = y


melisa1 [442]3 years ago
6 0

X = 3 · log(Y²)

X = 3 · 2·log(Y)

X/6 = log(Y)

10^(X/6) = 10^log(Y)

Y = 10^(X/6)

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Two or more velocities add by ____?<br><br> Plz help
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By vector addition.
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3 0
3 years ago
Read 2 more answers
Holding force constant, what will be the effect of increasing the Moment arm?
Murljashka [212]

Answer:

(b) Torque will increase.

Explanation:

Torque is given as the product of force and moment arm (radius).

τ = F x r

F = τ / r

where;

F is force

τ  is torque

r is radius (moment arm)

Keeping force constant, we will have the following;

τ ∝ r

This shows that torque is directly proportional moment arm (radius), thus increase in moment arm, will cause increase in torque.

For instance;

let the constant force = 5 N

let the initial moment arm, r = 2m

Torque, τ  = 5 N x 2m = 10 Nm

When the moment arm is increased to 4 m

Torque, τ  = 5 N x 4m = 20 Nm

Therefore, at a constant force, increasing in the Moment arm, will cause increase in torque.

Coorect option is "(b) Torque will increase."

5 0
3 years ago
The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}

(1)

y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s

(2)

y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s

(3)

y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

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He or she should follow her swing due to the momentum that was built
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PolarNik [594]

Answer:

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This ultimately implies that, the volume of an object in milliliters is equivalent to its volume in cubic centimeters.

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