It mimics the real world accurately
Explanation:
Experiments conducted in the field clearly presents the real world at it is to the scientist. Hardly can any part be controlled precisely and this gives a near to perfect scenario.
- In the laboratory, for example, an organism is isolated from its environment and might not fully display its natural instinct and physiological capabilities.
- Most laboratory set up are driven towards a model instead of real life settings.
- The laboratory is more controlled and less varied and might truly represent the real world. It will only portray a part of the real world and series of further tests might have to be carried out to have a better model.
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The physical activity that a global positioning system resource can help me with is : ( A ) Hiking
<h3>Function of Global positioning system ( GPS ) </h3>
GPS helps with the accurate measurement of physical activities and factors such as location, time, elevation and so on. When hiking, the time, distance covered and location of the hiker can be accurately measured with the use of the GPS.
Hence we can conclude that The physical activity that a global positioning system resource can help me with is Hiking.
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Answer:
50 lb
Explanation:
Given,
The weight of astronaut's life support backpack on Earth (w) = 300 lb
Acceleration due to gravity on Earth (g) = 9.8 m/s²
Acceleration due to gravity on Moon = g'
We know that weight of an object on Earth is,
Similarly, weight on Moon will be
Thus the astronaut's life support backpack will weigh 50 lb on Moon.
acceleration = Velocity changes ÷ time of the velocity changes
4 m/s^2 =
4 × 10^(-3) × 3600 km / h =
4 × 3.6 =
14.4 km / h
Thus :
14.4 = V(2) - V(1) / t(2) - t(1)
14.4 = V(2) - 20 / 10
Multiply both sides by 10
10 × 14.4 = 10 × ( V(2) - 20 ) / 10
144 = V(2) - 20
Add both sides 20
144 + 20 = V(2) - 20 + 20
V(2) = 164 Km/h
Thus the final velocity after 10 seconds is 164 Km/h .
