At the center of a 50 m diameter circular ice rink, if a 77 kg skater traveling at 2.3
m/s and then collides with a 63 kg skates traveling at 3.7 m/s. This is how
long it will take them to glide to the edge of the rink:
Speed after the collision= √{[77(2.3)77^2]
+ [63(3.7)^2]} / (77+63)=2.09 m/s
For them to be able to get to the edge
which is 50 m away it will take them 23.9
seconds.
Answer:
Assume two identical cans filled with two types of soup having same mass are rolling down on an inclined plane in same conditions. In terms of inertia different types of soup will indicate different viscosity. The higher viscosity fillings indicates more part of the soup mass is rotating together with the can’s body. This means that for the can with lower viscosity soup has a lower moment of inertia and the can with higher viscosity has higher moment of inertia while the same gravity makes them to roll.
incline angle = θ ; can's mass = m ; Radius of the can's = R , Angular acceleration for Can 1 = α1 ; Angular acceleration for Can 2 = α2
T1 = Inertia of Can with high viscosity soup
T2 = Inertia of Can with low viscosity soup
M1 rolling moment of Can 1
M2 rolling moment of Can 2
equation is given by
T1*α1 = M1 - (a)
T2*α2 = M2 - (b)
M1 = M2 = m*g*R*sin(θ). (c)
as assumed T1 > T2
from the three equation (a), (b) & (c)
the α2 > α1
Angular acceleration of Can 2 is higher than Can 1. Already stated that Can 1 has more viscous soup as compared to Can 2.
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
The ninth and 10th amendments refer that certain powers And laws be delegated to lower our governments i.e. state and local
