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3 years ago

During a solar eclipse our tiny moon totally blocks the sun because of .....

1 answer:

4 0

During a total solar eclipse, the moon passes between Earth and the sun. This completely blocks out the sun’s light. However, the moon is about 400 times smaller than the sun. How can it block all of that light?

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In the chemical formula for an ionic compound, which item is written first?

tatuchka [14]

Explanation:

.hahxxjdndjdndjgfndkndidjdodnxondos

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3 years ago

A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man accordi

RSB [31]

The velocity is 0.3 m/s South.

3 0

3 years ago

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A tennis ball of mass m=0.060 kg and speed v=25 m/s strikes a wall at a 45 angle and rebounds with the same velocity at 45°. Wha

Diano4ka-milaya [45]

To solve this problem we will apply the concepts related to the Impulse which can be defined as the product between mass and the total change in velocity. That is to say

$p = m\Delta v$

Here,

m = mass

$\Delta v =$ Change in velocity

As we can see there are two types of velocity at the moment the object makes the impact,

the first would be the initial velocity perpendicular to the wall and the final velocity perpendicular to the wall.

That is to say,

$v_i = vcos\theta$

$v_f = -v sin\theta$

El angulo dado es de 45° y la velocidad de 25, por tanto

$v_i = (25)cos(45) = 17.68m/s$

$v_f = -(25)sin(45) = -17.68m/s$

The change of sign indicates a change in the direction of the object.

Therefore the impulse would be as

$p = 0.060(-17.68-17.68)$

$p = -2.12kg \cdot m/s$

The negative sign indicates that the pulse is in the opposite direction of the initial velocity.

3 0

3 years ago

5. A 5.5 x10-6 C charge is located 0.28 m from a -3.5 x 10-6 C charge.

ra1l [238]

(a) The magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.

(b) If the negative charge is doubled, then the force will also get doubled.

The new force will be F = -4.418 N.

Explanation:

The force acting between two charged particles separated by a distance is termed as Coloumb's force or electrostatic force. It can be termed as electrostatic force of attraction if the the force acting between the charges are oppositely charged. And it can be termed as electrostatic force of repulsion if the charges are similar or like charges.

In the present case, there is a positive and negative charge, so electrostatic force of attraction will be acting between them. As per Coloumb's law, the electrostatic force of attraction is directly proportional to the product of charges and inversely proportional to the square of distance of separation.

$F = \frac{kQq}{d^{2} }$

Here, k is the constant of proportionality which is equal to 9 × $10^{9}$ and Q, q are the two charges, d is the distance of separation.

So here Q = 5.5 × $10^{-6} C$ and q = - 3.5 × $10^{-6} C$ and d = 0.28 m

Then, $F=-\frac{9*10^{9}*5.5*10^{-6} * 3.5 * 10^{-6} }{(0.28)^{2} } = 2209.82*10^{-3}$

So the magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.

(b) If the negative charge is doubled, then the force will also get doubled.

The new force will be F = -4.418 N.

3 0

4 years ago

Pls i need help really badly

melamori03 [73]

Answer:

the answer is write the bill of rights

8 0

3 years ago

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