The frequency f of the AC source is determined as 0.446 Xc.
<h3>
Frequency of the AC source</h3>
The frequency of the AC source is calculated as follows;
Xc ≡ 1/2fC
where;
- Xc is the capacitive reactance
- f is frequency
- C is capacitance
fC = 2Xc
f = 2Xc / C
f = (2Xc)/4.48
f = 0.446 Xc
Thus, the frequency f of the AC source is determined as 0.446 Xc.
Learn more about frequency here: brainly.com/question/10728818
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It's definitely not one of the graphs you gave us to choose from.
the answer would be touch and smell
Answer:
θ₂ ≈ 29.7°
Explanation:
Given:
n₁ = 1.33, n₂= 1.60, θ₁ = 36.6°, θ₂ = ?
Solution:
According to snell's Law
n₁ sin θ₁ = n₂ sin θ₂
1.33 × sin (36.6°) = 1.60 × sin θ₂
⇒ Sin θ₂ = 0.496
θ₂ ≈ 29.7°
C They are equal and opposite
