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Svetlanka [38]
2 years ago
9

Which equation correctly relates mechanical energy, thermal energy, and total energy when there is friction present in a system?

​
Physics
2 answers:
AleksAgata [21]2 years ago
6 0

Answer:

Ethermal = Etotal − ME

a p e x

fenix001 [56]2 years ago
4 0

Answer:ME=E TOTAL - E THERMAL

Explanation:JUST DID IT ON APEX

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A mover loads a 100 kg box into the back of a moving truck by pushing it up a ramp. The ramp is 4 m long and the back of the tru
elixir [45]

Answer:

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Explanation:aaaaaaaaaaaaaaaa

6 0
3 years ago
The 64.5-kg climber in is supported in the “chimney” by the friction forces exerted on his shoes and back. The static coefficien
kobusy [5.1K]

Answer:

The minimum force the climber must exert is about 439N.

Explanation:

We use the relationship between friction and normal force to answer this question:

F_{friction} = \mu_{static} \cdot F_{normal}\implies F_{normal}=\frac{F_{friction}}{\mu_{static}}

We are given the static coefficients of friction but need to determine the friction force. To do that we consider the totality of forces acting on this hapless gentleman stuck in a chimney. There is the gravity acting downward (+), then there are two friction forces acting upward (-), namely through his shoes and his back. The horizontal force exerted by the climber on both walls of the chimney is the same and is met with equally opposing normal force. Since the climber is not falling the net force in the vertical direction is zero:

F_{net} = 0 = F_g - F_{shoes}-F_{back}= mg - \mu_{shoes}F_{norm}-\mu_{back}F_{norm}\\F_{norm}=\frac{mg}{\mu_{shoes}+\mu_{back}}=\frac{64.5kg\cdot 9.8\frac{m}{s^2}}{0.8+0.64}\approx 438.96N\\

The normal force in this equilibrium is about 439N and  because we are told that the static friction forces are both at their maximum, this value is at the same time the <em>minimum</em> force needed for the climber to avoid starting slipping down the chimney.



7 0
2 years ago
How many grams does 15.58 L of gasoline weigh? Gasoline has a density of 0.74 g/mL
Korolek [52]

We are given volume of gasoline = 15.58 L and

Density = 0.74 g/mL.

Density is given in grams(g) per milliliter (mL). So, we need to convert given volume in mL also.

We know, 1 litre = 1000 milliliters

Therefore, 15.58 L = 15.58 * 1000 mL = 15580 mL

We could rewrite,

Volume of gasoline = 15580 mL.

Formula for density is..

Density (ρ)= \frac{Mass}{ Volume}

Plugging values in formula,

0.74  g/mL = \frac{Mass}{15580 \ mL}

Muliplying both sides by 15580.

0.74 g/mL * 15580mL =\frac{Mass}{15580 \ mL} * 15580mL

11529.2g = mass.

Therefore, 11529.2g grams does 15.58 L of gasoline weigh.




5 0
3 years ago
A ball is thrown upward. As it passes 5.0 m height it is traveling at 4.0 m/s up. What was its initial upward velocity? (a) 7.0
sveticcg [70]

Answer:

c) 10.7m/s

Explanation:

From the exercise we know that at 5m the ball  is traveling at 4m/s

To calculate its initial velocity we need to solve the following equation:

v_{y}^{2}=v_{oy}^{2}+2g(y-y_{o})

Since the initial height is 0

Solving for v_{o}

v_{oy}=\sqrt{v_{y}^{2}-2gy}=\sqrt{(4m/s)^2-2(-9.8m/s^2)(5m)}=10.7m/s

5 0
3 years ago
Ideally, rewards should be given immediately and frequently but
snow_lady [41]
The correct answer for the question that is being presented above is this one: "a. only from an instructor or supervisor." Ideally, rewards should be given immediately and frequently but <span>only from an instructor or supervisor to show authority. </span>
3 0
2 years ago
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