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Nata [24]
3 years ago
14

5. Steve is driving in his car to take care of some errands. The first errand has him driving to a location 2 km East and 6 km N

orth of his starting location. Once he completes that errand, he drives to the second one which is 4 km East and 2 km South of the first errand. What is the magnitude of the vector that describes how far the car has traveled from its starting point, rounded to the nearest km?​
Physics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

gshshs

Explanation:

hshsksksksbsbbshd

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Two bikers are riding a circular
OverLord2011 [107]
ANSWER.no cause they have to be going a the same speed and I doubt that are gonna go at the same speed.
8 0
3 years ago
A blue car pulls away from a red stop-light just after it has turned green with a constant acceleration of 0.2 m/s2. A green car
jolli1 [7]

Answer:

After 15 seconds, the green car will catch up with the blue car

Explanation:

Let the time for the green car to catch up with the blue car be T

When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal

Distance covered by blue car after time T is given by: s = ut + 0.5 at²

Where u = 0, a = 0.2 m/s², t = T

S = 0.5 × 0.2 × T² = 0.1 T²

Velocity of blue car, v = u+ at

v = 0.2T

Distance covered by green car at T is given as: S = Velocity × time

Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)

S = 0.2T (T - 7.5)

S = 0.2 T² - 1.5T

Equating the distance covered by the two cars

0.2T² - 1.5T = 0.1T²

0.1T² - 1.5T = 0

T(0.1T - 1.5) = 0

T = 0 or

T = 1.5/0.1 = 15 secs

Therefore, after 15 seconds, the green car will catch up with the blue car

8 0
3 years ago
A 0.200-kg cube of ice (frozen water) is floating in glycerine.The gylcerine is in a tall cylinder that has inside radius 3.90 c
natita [175]

Answer:

Part a)

h = 0.86 cm

Part b)

Level will increase

Explanation:

Part a)

Mass of the ice cube is 0.200 kg

Now from the buoyancy force formula we know that weight of the ice is counter balanced by buoyancy force on the ice

So here we will have

mg = \rho V_{displaced} g

V_{displaced} = \frac{m}{\rho}

V_{displaced} = \frac{0.200}{1260} = 1.59 \times 10^{-4} m^3

now as we know that ice will melt into water

so here volume of water that will convert due to melting of ice is given as

V\rho_w = m_{ice}

V = \frac{0.200}{1000} = 2\times 10^{-4} m^3

So here extra volume that rise in the level will be given as

\Dleta V = V - V_{displaced}

\pi r^2 h = 2\times 10^{-4} - 1.59 \times 10^{-4}

(\pi (0.039^2) h = 0.41 \times 10^{-4}

h = 0.86 cm

Part b)

Since volume of water that formed here is more than the volume that is displaced by the ice so we can say that level of liquid in the cylinder will increase due to melting of ice

5 0
4 years ago
Our Sun is a_________ star.
aliina [53]
NAMASTE :)

HERE IS YOUR ANSWER:

Our Sun is a \boxed{high- temperature } star.
5 0
3 years ago
Read 2 more answers
5. Sarah is standing 32.0 m away from Jason. If Sarah throws a snowball at a 45 degree
padilas [110]

Answer:

Explanation:

If air resistance is ignored and assume UP and Toward Jason are the positive directions.

horizontal analysis

d = (vx₀)t

t = d/vx₀

horizontal analysis

0 = vy₀t + ½gt²

0 = vy₀(d/vx₀)+ ½g(d/vx₀)²

as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.

0 = d + ½g(d²/v₀²cos²45)

-d = ½g(d²/v₀²cos²45)

-dv₀² = ½g(d²/cos²45)

   v₀² = -½g(d/cos²45)

   v₀² = -½(-9.81(32.0/cos²45)

   v₀² = 313.92

   v₀ = 17.717787...

   v₀ = 17.7 m/s

7 0
3 years ago
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