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Nata [24]
3 years ago
14

5. Steve is driving in his car to take care of some errands. The first errand has him driving to a location 2 km East and 6 km N

orth of his starting location. Once he completes that errand, he drives to the second one which is 4 km East and 2 km South of the first errand. What is the magnitude of the vector that describes how far the car has traveled from its starting point, rounded to the nearest km?​
Physics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

gshshs

Explanation:

hshsksksksbsbbshd

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At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and
Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

1atm = 2116lb/ft^2

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

n = Amount of substance (at this case the mass)

Then

\frac{n}{V} = \frac{P}{RT}

The amount of substance per volume is the density, then

\rho = \frac{P}{RT}

Replacing with our values,

\rho = \frac{5.6*2116}{1716*850}

\rho = 0.00812slug/ft^3

Finally the specific volume would be

v = \frac{1}{\rho}

v = 123ft^3/slug

6 0
3 years ago
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

7 0
3 years ago
20 POINTS!!!
hram777 [196]
I think its inductance. If its not then I think its none of the above
5 0
3 years ago
You leave your bicycle out in the rain and it rust is a physical or chemical change
Alexxx [7]
It’s a chemical change
3 0
3 years ago
Read 2 more answers
A 11 g plastic ball is moving to the left at 29 m/s. How much work must be done on the ball to cause it to move to the right at
Rasek [7]

Answer:

4.25 J

Explanation:

Given that

mass of plastic ball = 11 g

Mass of plastic ball = 0.011 kg

velocity of ball = 29 m/s

We know that from work power energy theorem

W_{all}=Change\ in\ kinetic\ energy\ of\ system

We know that kinetic energy of moving mass given as

KE=\dfrac{1}{2}mv^2

Now by pitting the values

KE=\dfrac{1}{2}mv^2

KE=\dfrac{1}{2}\times 0.011\times 29^2

KE= 4.25 J

So the work done on the ball is 4.25 J

8 0
3 years ago
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