Question

Simplify (3x^2 y)^-3

Answer 1

we are given

$(3x^2 y)^{-3}$

firstly , we can make exponent positive

$\frac{1}{(3x^2y)^3}$

now, we can distribute exponent

$\frac{1}{(3x^2)^3(y)^3}$

$\frac{1}{(3)^3(x^2)^3(y)^3}$

we can combine exponents

and we get

$\frac{1}{27x^6y^3}$...........Answer

Answer 2

$(3x^{2}y)^{-3} =\frac{1}{(3x^{2}y)^{3}} = \frac{1}{27x^{6}y^{3}}$