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malfutka [58]
3 years ago
13

Where does radioactivity come from?

Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

C. radioactive material

Explanation:

This exposure primarily comes from cosmic rays, radioactive material in the earth (such as uranium-238), ingestion of naturally occurring radionuclides in food (such as potassium- 40), and inhalation of radon gas. In the United States, the average background radiation dose is 300 mrem/yr.

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To study a key fuel-cell reaction, a chemical engineer has 20.0-L tanks of H₂ and of O₂ and wants to use up both tanks to form 2
Lapatulllka [165]

the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Given , to study a key fuel-cell reaction , a chemical engineer has 20.0L tanks of H2 and O2 and wants to use up both tanks to form 28.0mol of water at 23.8°C .

the reaction of the fuel cell is given by ,

H2(g) +1/2 O2 ( g) →H2O

Moles of H2 required = 28 mol

moles of O2 required = 14mol

Now according to van der waals equation ,

p= (nRT/ V-nb)  - an^2 / V^2

for H2 , a = 0.2453L^2bar /mol^2 , b= 0.02651L/mol

P for H2

= (28×0.0821×296.8/20-28×0.02651 ) -(0.2456 ×28×28/20×20)

P for H2 = 35.4291079-0.481376 = 34.9477319 atm

for O2 ,  a = 1.38L^2bar/mol^2 , b = 0.03186L/mol

P for O2 = (14×0.0821×296.8 /20-14×0.03186) - (1.382×14×14/20×20)

P for O2 = 17.4461807 - 0.67718 =16.7690007 atm

Hence , the pressure needed on H2 tank is 34.9477319atm and the pressure needed in O2 tanks is 16.7690007atm .

Learn more about pressure here :

brainly.com/question/25965960

#SPJ4

6 0
1 year ago
Help please!
serious [3.7K]
I think that the empirical formula is mgcl2

3 0
3 years ago
How many atoms are in each compound ?
noname [10]
Compounds are made of two or more atoms of different elements, such as water (H2O) and methane (CH4). Atoms are not drawn to scale. Molecules of compounds have atoms of two or more different elements.
7 0
3 years ago
An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatica
NISA [10]

Answer:

6.15.3 k

Explanation:

From the question we can see that

q = 0,  Δu = w

Then,

T_f = \frac{C_{V,m}+RP_{ext}P_i}{C_{V,m}+RP_{ext}P_f} T_i

putting values wet

=\frac{2.5\times 8.314+8.314\left(10^5\right)\left(3.20\times 10^5\right)}{2.5\times 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right)}\times \:293

T_f = 615.3 K

6 0
3 years ago
PLZ HELP PLZ SOMEONE PLZ How old do u need to work as a secret agent
zmey [24]

I THINK 18 OR 21 I AM SORRY IF I AM WRONG BRO

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3 years ago
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