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Vlad1618 [11]
3 years ago
6

How many ions are there in 0.187 mol of Na+ ions

Chemistry
2 answers:
kondaur [170]3 years ago
4 0
Best Answer
1 mole of a substance contains 6.022x10^23 "units" of that substance.

So 0.187 mol of Na+ is 1.13x10^23 ions (6.022x10^23 x 0.187).
Greeley [361]3 years ago
3 0

Answer : The number of ions present in 0.187 mole of sodium ions are, 1.163\times 10^{23}

Solution : Given,

Moles of sodium ions = 0.187 moles

As we know that

1 mole of substance contains 6.22\times 10^{23} number of ions

So, 0.187 moles of substance contains 0.187\times (6.22\times 10^{23})=1.163\times 10^{23} number of ions

Therefore, the number of ions present in 0.187 mole of sodium ions are, 1.163\times 10^{23}


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Answer:

3.2×10^-3 mol

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

The question gives you the volume in mL, so to convert "mL" to "L" you need to divide by 1000. (6.70mL/ 1000L)= 0.0067L.

Now you can plug the numbers into the equation. 0.480M= n/ 0.0067L), multiply (0.480M×0.0067L)= 0.003216 mol. The scientific notation is 3.2×10^-3, 10^-3 because you move the decimal back three times and 3.2 because there are 2 sig figs.

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