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Zigmanuir [339]
4 years ago
14

A student takes some data with a cart rolling on an inclined track and produces the following set of data: From the graphs and l

ine fit, determine the following quantities: The position of the cart at time t = 0: x0 = 0.3 m Correct: Your answer is correct. The initial velocity: v0 = 0.30 m/s Correct: Your answer is correct. The acceleration: a = 0.205 m/s2 Correct: Your answer is correct. The position at time t = 0.40 s: x(0.40 s)= 0.904 m Incorrect: Your answer is incorrect. The velocity at time t = 0.50 s: v(0.50 s)= 0.403 m/s Correct: Your answer is correct.
Physics
1 answer:
ivolga24 [154]4 years ago
7 0

Answer:

x_f = 0.4364 m

Explanation:

As we know that initial velocity of the cart is given as

v_i = 0.30 m/s

initial position is given as

x_i = 0.30 m

acceleration of the cart is given as

a = 0.205 m/s^2

now position of the cart after t= 0.40 s is given as

x_f = x_i + v_i t + \frac{1}{2}at^2

x_f = 0.30 + 0.30(0.40) + \frac{1}{2}(0.205)(0.40^2)

x_f = 0.4364 m

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Marizza181 [45]

Answer:

Explanation:

Given

mass of object m=7 kg

kinetic Energy k=36\ J

Tension in string T=326\ N

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore T=\frac{mv^2}{r}----1

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