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Ivahew [28]
3 years ago
5

After setting up stereo speakers in your schools music room, you notice that in certain areas of the room, the sound from the sp

eakers is very loud. In other areas, the sound is very soft. Using the concept of interference, explain why the sound levels in the music room vary.
Physics
1 answer:
Keith_Richards [23]3 years ago
3 0

Answer:Explained Below

Explanation:

Loud sound is because of constructive interference of sound waves and soft sound is due to destructive interference of sound waves.

Constructive interference is when two waves of same sign amplitude combines to form a louder sound and opposite sign for destructive interference.

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Answer:

The excess charge is Q  = 3.5 *10^{-7} \ C

Explanation:

From the question we are told that

      The diameter is d = 45 \ cm  =  0.45 \ m

       The potential of the surface is V =  14 \ kV   =  14 *10^{3} \ V

     

The radius of the sphere is  

           r = \frac{d}{2}

substituting values

          r = \frac{0.45}{2}

         r = 0.225 \ m

The potential on the surface is mathematically represented as  

          V  =  \frac{k  *  Q  }{r }

Where k is coulomb's constant with value  k  =  9*10^{9}  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

  given from the question that there is no other charge the Q is the excess charge  

Thus  

        Q  =  \frac{V* r}{ k}

substituting values

        Q  =  \frac{14 *10^{3}  0.225}{ 9*10^9}

        Q  = 3.5 *10^{-7} \ C

         

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Answer:

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Let's analyze the statements time

A. False. We saw that it deviates

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C. False It deviates, but it is not parallel to normal

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