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3 years ago

This diagram shows the magnetic field lines near the ends of two magnets. There is an error in the diagram.

Physics

2 answers:

ss7ja [257]3 years ago

8 0

Answer:

C-Changing the S to N

Explanation:

As we know that magnetic field lines originated from North pole of magnet and then terminate into the south pole of magnet.

Now if we put similar poles of magnet in front of each other then we can say that the magnetic field lines of two poles will repel each other and due to this two similar poles have repulsion force.

Similarly if two different poles of magnet will place in front of each other then the magnetic field lines will originate from north pole and terminate at south pole.

This will show attraction force between the poles of magnet.

Now we can see the figure that magnetic field lines are originating from both poles here as well as these lines are repelling each other.

So here both poles must have North pole

So correction here must be

C)-Changing the S to N

hoa [83]3 years ago

4 0

I believe the answer is c

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andrew11 [14]

Answer:

Explanation:

Given that,

A point charge is placed between two charges

Q1 = 4 μC

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We want to find the point when the electric field will be zero.

Electric field can be calculated using

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Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.

Then, the magnitude of the electric at point x is zero.

E = kQ1 / r² + kQ2 / r²

0 = kQ1 / x² - kQ2 / (1-x)²

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Divide through by k

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4μ / x² = 1μ / (1 - x)²

Divide through by μ

4 / x² = 1 / (1-x)²

Cross multiply

4(1-x)² = x²

4(1-2x+x²) = x²

4 - 8x + 4x² = x²

4x² - 8x + 4 - x² = 0

3x² - 8x + 4 = 0

Check attachment for solution of quadratic equation

We found that,

x = 2m or x = ⅔m

So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.

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3 years ago

Find the product of 30−−√ and 610−−√. Express it in standard form (i.

Helen [10]

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3 years ago

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3 years ago

a box has a momentum of 1.30 kg*m/s to the right. a 12.8 N force pushes it to the right for 0.218 s. what is the final momentum

Rufina [12.5K]

Answer:

4.09 kgm/s

Explanation:

Concept tested: Second Newton's law of motion

So what does the second Newton's law of motion state?

According to the second Newton's law of motion, the resultant force and the rate of change of momentum are directly proportional.

That is; $F=\frac{(mVf-mVo)}{t}$ , where, mVf is the final momentum and mVo is the initial momentum.

In this case;

Force = 12.8 N
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Time, t = 0.218 seconds

Therefore; replacing the values of the variables in the formula;

we get;

$12.8N=\frac{(mVf-1.3kgm/s)}{0.218s}$

$(12.8N)(0.218s)=(mVf-1.3kgm/s)$

$2.7904+1.3=mVf$

Solving for final momentum;

$mVf =4.0904 kgm/s$

= 4.09 kgm/s

Therefore, the final momentum of the box is 4.09 kgm/s

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3 years ago

A relaxed biceps muscle requires a force of 25.0 N for an elongation of 3.0 cm; the same muscle under maximum tension requires a

Verizon [17]

Answer:

$3.3\times10^{4} Pa$

$6.67\times10^{5} Pa$

Explanation:

Complete statement of the question is

A relaxed biceps muscle requires a force of 25.0 N for an elongation of 3.0 cm; the same muscle under maximum tension requires a force of 500 N for the same elongation. Find Young's modulus (Pa) for the muscle tissue under each of these conditions .The muscle is assumed to be a uniform cylinder with length 0.200 m and cross-sectional area 50.0 cm^2.

For relaxed muscle :

$F$ = force required = 25 N