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Lilit [14]
3 years ago
11

A mile is equivalent to 1.6 km. When you are driving at 60 miles per hour, what is your speed in meters per second?

Physics
1 answer:
yKpoI14uk [10]3 years ago
6 0
FIrst, just write down what we know :)

1. 1 mile = 1.6klm
2. There are 3600 seconds in an hr (<em>60s x 60mins = 3600</em>).

Now to get to <em>meters per second</em> (m/s) we need to first work out <em>meters per </em><em>hr</em> (simply convert miles to klm and then multiply by 1000)<em>.</em>

60 x 1.6 = 96 klm/hr x 1000 = 96,000 meters/hr

Now we know this, we can simply divide the meters per hr by <em>how many seconds there are in 1hr</em> to get meters per second:

96000 / 3600 = 26.67m/s
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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th
ipn [44]

Answer:

a) F_{fric} = 692 N

b) F_{applied} = 932 N

Explanation:

a)

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object  in all directions.

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

F_{applied} = 800 N

Mass = m = 90 kg

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F_{fric} = ?

800 - F_{fric} = (90)(1.2)

F_{fric} = 692 N

b)

According to newton's second law of motion,

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

If we assume the same friction and acceleration between player's feet and ground as calculated in part a

F_{fric} = 692 N

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We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.

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F_{applied} - 692 N = (200)(1.2)

F_{applied} = 692 + 240

F_{applied} = 932 N

7 0
4 years ago
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