What is the volume of 45.6 g of silver if the density of silver is 10.5 g/ml?
2 answers:
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Answer:
You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.
Explanation:
Given Values:
L = 50 cm = 0.5 m
H = 170 j/s
To find the diameter of the rod, we have to find the area of the rod using the following formula.
Here Tc = 100.0° C
k = 50.2
H = k × A ×
Solving for A
A =
A =
A = = 6.77 ×
m²
Now Area of cylinder is :
A = d²
solving for d:
d =
d = 9.28 cm
Explanation:
Th electric force between charges is inversely proportional to the square of distance between them. It means,
Initial distance, r₁ = 2 cm
Final distance, r₂ = 0.25 cm
Initial force, F₁ = 1 N
We need to find the electric force between charges if the new separation of 0.25 cm. So,
So, the new force is 64 N if the separation between charges is 64 N.