the police department determined that the force required to drag a 130 N(29 lb) car tire across the pavement at a constant veloc
1 answer:
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Answer:
Option d and e are correct.
Explanation:
The expression for velocity of pulse in a stretched string can be given as follows
v =
where T is tension in the string , m is mass of string per unit length.
Use of lighter string of the same length, under the same tension amounts to higher m so velocity will decrease. Hence option d is correct.
Similarly, v is directly proportional to square root of tension. So if we increase tension , velocity also increases. So option e ) is correct.
Answer:
(a)
(b) The force is repulsive
Explanation:
a) According to Coulomb's law, the magnitude of the electrice force that one particle exerts on the other is defined as:
Here k is the coulomb constant, and
are the signed magnitudes of the charges and d is the distance between them.
b) According to Coulomb's law, if the two charges have the same sign, the electrostatic force between them is repulsive.
Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.
Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.