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Rudik [331]
3 years ago
12

4. Each time that you prepare a diluted bleach solution you will want it to have a [OH-] = 0.02. Calculate how much 1.00 M NaOH

you need to add to d.1. water to get every 20 mL of this concentration of OH- ion. Express your answer in drops of 1.00 M NaOH. (Assume that there are 20 drops in 1 m.)
Chemistry
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

8 drops of 1.00 M NaOH will be needed.

Explanation:

Concentration of [OH^-] in bleach solution = 0.02 M

NaOH\rightarrow OH^-+Na^+

NaOH=[OH^-]=0.02M

Concentration of bleach solution we want ,M_1 = 0.02 M

Volume of the bleach solution,V_1 = 20 ml

Concentration of NaOH solution,M_2 = 1.00 M

Volume of the NaOH solution required ,V_2 = ?

M_1V_1=M_2V_2

0.02 M\times 20 mL=1.00 M\times V_2

V_2=\frac{0.02 M\times 20 mL}{1.00 M}=0.4 mL

1 mL = 20 drops

0.4 mL = 0.4 × 20 drops = 8 drops

8 drops of 1.00 M NaOH will be needed.

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What type of reaction does each of the following equations represent?
vekshin1

Answer:

Option C. Decomposition

Explanation:

To know which option is correct, it is important we know what is a single displacement reaction, double displacement reaction and decomposition reaction.

A Single displacement reaction can be defined as a reaction in which a single element is replaced by another element in a compound.

A double displacement reaction is a reaction involving the exchange of ions of two parts of ionic compounds to form two different compounds.

A decomposition reaction is a reaction in which a compound splits into two or more simpler compound or element.

Bearing the above definitions in mind and considering the question given above, we can conclude that the reaction given in the question above is a decomposition reaction since the compound (NH₄OH) splits into two different compound (NH₃ and H₂O)

3 0
2 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

4 0
3 years ago
The most common compound on earht is:
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The most common compound on earth is cellulose because it has enough energy to be the next source for biofuels. 
6 0
3 years ago
the rate of disappearance of Br- at some moment in time was determined to be 3.5 x 10-4 M/s. What is the rate of appearance of B
ddd [48]

Answer:

1.8 × 10⁻⁴ mol M/s

Explanation:

Step 1: Write the balanced reaction

2 Br⁻ ⇒ Br₂

Step 2: Establish the appropriate molar ratio

The molar ratio of Br⁻ to Br₂ is 2:1.

Step 3: Calculate the rate of appearance of Br₂

The rate of disappearance of Br⁻ at some moment in time was determined to be 3.5 × 10⁻⁴ M/s. The rate of appearance of Br₂ is:

3.5 × 10⁻⁴ mol Br⁻/L.s × (1 mol Br₂/2 mol Br⁻) = 1.8 × 10⁻⁴ mol Br₂/L.s

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2 years ago
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Answer:

Erosion

Explanation:

3 0
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