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Sav [38]
3 years ago
7

Please, answer thank you

Mathematics
2 answers:
Musya8 [376]3 years ago
7 0

Between 1 and 2 tons because one ton is 2,000 pounds and 2 tons is 4,000 pounds

wolverine [178]3 years ago
5 0

B.)between 3 and 4 tons.

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The diameter of a round patio is 16 feet.Which expression can be used to find the patio’s circumference in feet?
Delicious77 [7]

Answer: 16*pi

Step-by-step explanation: The equation for diameter is pi*diameter. Since you already know the diameter, just plug it in.

8 0
3 years ago
PLEASE HELP FAST I NEED IT DONE IS OVERDUE
erica [24]

Answer:

D. (7,5)

Step-by-step explanation:

Imagine a full parallelogram, complete the shape from there

6 0
2 years ago
Terrell is moving boxes in a freight elevator. Each box weighs about 25 pounds. For safety reasons, a maximum of 600 pounds can
k0ka [10]

Answer:

x ≤ 15

Step-by-step explanation:

25x + 225 ≤ 600

Subtract 225 from both sides and get

25x  ≤  375

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3 0
3 years ago
7.98 is 1/10 of what number?
Lyrx [107]

Answer:

79.8

Step-by-step explanation:

7.98*10=

79.8

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(1/10)*79.8=

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7 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
2 years ago
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