Speed x time = distance
Distance divided by time = speed
500 divided by 5
Speed = 100
Answer:
2.1406 × m/sec
Explanation:
we know that energy is always conserved
so from the law of energy conservation
here V is the potential difference
we know that mass of proton = 1.67× kg
we have given speed =50000m/sec
so potential difference
now mass of electron =9.11×
so for electron
so the velocity of electron will be 2.1406× m/sec
Answer:
The best estimate of the depth of the well is 2.3 sec.
Explanation:
Given that,
Record time,
We need to find the best estimate of the depth of the well
According to record time,
We can write of the record time
Here, all time is nearest 2.3 sec.
So, we can say that the best estimate of the depth of the well is 2.3 sec.
Hence, The best estimate of the depth of the well is 2.3 sec.
Explanation:
We have,
Semimajor axis is
It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :
G is universal gravitational constant
M is solar mass
Plugging all the values,
Since,
So, the orbital period of a dwarf planet is 138.52 years.
In order to give a spaceship at rest in a specific reference frame s a speed increment of 0.500c, seven increments are required. Then, in this new frame, it receives an additional 0.500c increment.
The speed of an object, also known as v in kinematics, is a scalar quantity that refers to the size of the change in that object's position over time or the size of the change in that object's position per unit of time. The distance travelled by an object in a certain period of time divided by the length of the period gives the object's average speed in that period.
The spacecraft moves at v1 = 0.5c after the initial increment.The equation becomes V2 = V+V1/1+V*V1/c after the second one. 2 V2 = 0.5c+0.50c/1+(0.50c)^2/c^ 2 = 0.80c
Likewise, V3 = 0.929c
V4 = 0.976c
V5 = 0.992c
V6 = 0.99c
V7 = 0.999c
Learn more about speed here
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