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lozanna [386]
3 years ago
11

I need help fast please help

Physics
1 answer:
Irina18 [472]3 years ago
5 0
A and C Im pretty sure :)
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One billiard ball is shot east at 2.2 m/s. A second, identical billiard ball is shot west at 0.80 m/s. The balls have a glancing
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(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

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Using law of conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Along X- axis

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v_{1}=1.4i\ m/s

Along Y-axis

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m_{1}v_{1}=-m_{2}v_{2}

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Then the final speed of the first ball

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(b) We need to calculate the direction of the first ball after the collision

Using formula of direction

\tan\theta=\dfrac{v_{2}}{v_{1}}

\tan\theta=\dfrac{-1.36}{1.4}

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\theta=-44.16^{\circ}

Negative sign shows the direction of first ball .

Hence, (a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

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