Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance
Where, d = distance
A = amplitude
Put the value into the formula
Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
<span>c. run towards a source of water to extinguish the fire
</span>
The answer is Density !, Do you also need an example ?
Rate this the brainliest answer , Thank youuu !
Answer:
Explanation:
Given:
- mass of solid cylinder,
- diameter of cylinder,
- mass of bucket of water,
<em>When the bucket is released to fall in the well, it fall under the acceleration due to gravity.</em>
We have formula for angular acceleration as:
where:
g = acceleration due to gravity
r = radius of the cylinder
Answer:
The speed of the large cart after collision is 0.301 m/s.
Explanation:
Given that,
Mass of the cart,
Initial speed of the cart,
Mass of the larger cart,
Initial speed of the larger cart,
After the collision,
Final speed of the smaller cart, (as its recolis)
To find,
The speed of the large cart after collision.
Solution,
Let is the speed of the large cart after collision. It can be calculated using conservation of momentum as :
So, the speed of the large cart after collision is 0.301 m/s.