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3 years ago

Is the combustion of gasoline endothermic or exothermic?

Chemistry

1 answer:

UNO [17]3 years ago

5 0

The reaction would be Exothermic

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#1. Which one of the following statements correctly defines active site? The active site is a site on the enzyme molecule where

deff fn [24]

Active sites in enzymes are where substrates bind. Once they bind, a catalytic reaction occurs as a complex between substrate and enzyme is formed. Enzymes are termed as biocatalysts or simply catalysts since they speed up the catalytic reaction. After the reaction, they simply revert back to their original form, after having adjusted to fit with substrate.

7 0

3 years ago

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.

Papessa [141]

Answer: The value of equilibrium constant for the net reaction is 11.37

Explanation:

The given chemical equations follows:

Equation 1: $A+2B\xrightarrow[]{K_1} 2C$

Equation 2: $2C\xrightarrow[]{K_2} D$

The net equation follows:

$D\xrightarrow[]{K} A+2B$

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K=K_1\times \frac{1}{K_2}$

We are given:

$K_1=2.57$

$K_2=0.226$

Putting values in above equation, we get:

$K=2.57\times \frac{1}{0.226}=11.37$

Hence, the value of equilibrium constant for the net reaction is 11.37

6 0

3 years ago

Which compound has the highest melting point?

motikmotik

I think b carbon dioxide

3 0

3 years ago

What is the temperature in kelvin for 50 celsius?

strojnjashka [21]

Answer:

323.15

Explanation:

323.15

8 0

3 years ago

Read 2 more answers

Number of molecules of water in 6 moles

Anit [1.1K]

I mol of anything is 6.02 * 10^23 (in this case molecules of water)
6 mols of water = x

1/6 = 6.02 * 10^23 / x Cross multiply
x = 6 * 6.02* 10^23
x = 3.612 * 10^24 molecules in 6 mols of water

5 0

3 years ago