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Andrej [43]
3 years ago
13

Why do we have to reduce​

Chemistry
1 answer:
sdas [7]3 years ago
7 0

Answer:BECAUSE YOU DO I don’t know ask google

Explanation:

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Answer:

yes

Explanation:

because it help the body hydrate

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3 years ago
Someone help me with this ASAP! ^_^
kaheart [24]
I think it’s C sry if I’m wrong
4 0
3 years ago
Read 2 more answers
HELPP
slamgirl [31]

Answer:

In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.

Explanation:

tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:

\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=

mass compound

mass H

×100%

\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=

mass compound

mass C

×100%

If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:

\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=

10.0g compound

2.5g H

×100%=25%

\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=

10.0g compound

7.5g C

×100%=75%

7 0
3 years ago
C2d3 has a solubility product constant of 9.14×10−9. What is the molar solubility of c2d3?
shutvik [7]

Answer : The molar solubility of C_2d_3 is 9.67\times 10^{-3}M

Explanation :

The solubility equilibrium reaction will be:

C_2d_3\rightleftharpoons 2C^{3+}+3d^{2-}

The expression for solubility constant for this reaction will be,

Let the molar solubility be, 'x'

K_{sp}=(2x)^2\times (3x)^3

Now put all the given values in this expression, we get:

9.14\times 10^{-9}=108x^5

x=9.67\times 10^{-3}M

Therefore, the molar solubility of C_2d_3 is 9.67\times 10^{-3}M

5 0
3 years ago
........................................................
vaieri [72.5K]

Answer:

whats the question

Explanation:

5 0
3 years ago
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