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The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.
<h3>What is ksp?</h3>
Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.
Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water
The solution equilibrium is
Ca(OH)² = Ca + 2OH
The molar solubility is
0.186 / 74.00 / 0.230 = 0.0109 M
The ksp value will be
Ksp = (s) (2S)²
Putting the values in the formula
(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.
Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.
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Answer:
C Beause energy can't be carred with the water to the shore
Explanation:
Following reaction is involved in above system
HOCl(aq) ↔ H+(aq) + OCl-<span>(aq)
</span>OCl-(aq) + H2O(l) ↔ HOCl(aq) + OH-<span>(aq)
</span>
Now, if the system is obeys 1st order kinetics we have
K = [OCl-][H+<span>]/[HOCl] ............. (1)
</span>∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8<span>) ............. (2)
</span>
and now considering that system is obeying 2nd order kinetics, we have
K = [OH-][HOCl-] / [OCl-] ................. (3<span>)
</span>Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8<span>)
</span>we know that, [OH-][H+] = 10<span>-14
</span>∴K = 3.3 * 10<span>-7
</span>
Thus, correct answer is e i.e none of these
