1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
3 years ago
9

The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat

liquid = 1.74 J/g°C At a pressure of 1 atm, what is H in kJ for the process of condensing a 24.8 g sample of gaseous benzene at its normal boiling point of 80.1 °C. kJ
Chemistry
1 answer:
user100 [1]3 years ago
6 0

<u>Answer:</u> The heat required for the process is 4.24 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of benzene = 24.8 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = ?

n = number of moles = 0.318 moles

\Delta H_{rxn} = enthalpy change of the reaction  = 30.7 kJ/mol

Putting values in above equation, we get:

30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ

Hence, the heat required for the process is 4.24 kJ

You might be interested in
Can you balance 12 blocks on the 3x2 platform
Jobisdone [24]
Yes, it is possible to go do because it would be 2 stacks of 6
3 0
2 years ago
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . suppose 1
Aleks04 [339]
The answer is yes I think
5 0
3 years ago
Please help me with dis
topjm [15]

Answer:

c

Explanation:

4 0
3 years ago
The pH of a 0.150 molar solution of a weak acid is 4.10. What is the pKa of the acid?
Kamila [148]
Answer: 4.21×10⁻⁸

Explanation:


1) Assume a general equation for the ionization of the weak acid:

Let HA be the weak acid, then the ionization equation is:

HA ⇄ H⁺ + A⁻

2) Then, the expression for the ionization constant is:

Ka = [H⁺][A⁻] / [HA]

There, [H⁺] = [A⁻], and [HA] = 0.150 M (data given)


3) So, you need to determine [H⁺] which you do from the pH.

By definition, pH = - log [H⁺]

And from the data given pH = 4.1


⇒ 4.10 = - log [H⁺] ⇒ [H⁺] = antilog (- 4.10) = 7.94×10⁻⁵

4) Now you have all the values to calculate the expression for Ka:

ka = 7.94×10⁻⁵ × 7.94×10⁻⁵ / 0.150 = 4.21×10⁻⁸
3 0
3 years ago
Read 2 more answers
Predict the geometry about each interior atom in acetic acid:
aleksandr82 [10.1K]

The atomic structure of the acetic acid is:

                        H     O

                        l       l

                H – C – C – O – H

                        l

                        H

 

We can see from the structure that there are 2 interior atoms, and these are all Carbon atoms.


The geometry is:

Tetrahedral on First Carbon

Trigonal Planar on Second Carbon

5 0
3 years ago
Other questions:
  • A chemist wants to uncover evidence that when molecules of a gas strike the wall of a container, energy is transferred from the
    13·1 answer
  • A submicroscopic particle suspended in a solution has a volume 1.3um^3. What is this volume in liters?
    14·2 answers
  • Electrical charge may be rapidly moved from one body to another by means of a(n)
    8·2 answers
  • What other elements does zinc bond with?
    15·1 answer
  • The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
    6·2 answers
  • I need help please.
    5·1 answer
  • How many moles of SnF₂ will be produced along with 48 grams of H₂? *
    12·1 answer
  • The concentration of hydrogen peroxide solution can be determined by
    13·1 answer
  • Please help me fast ​
    11·1 answer
  • What makes people more vulnerable to addition​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!