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mafiozo [28]
3 years ago
10

A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution? Use the peri

odic table in the toolbar if needed.
Chemistry
2 answers:
meriva3 years ago
7 0
The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:

m_{NaOH}=25.00\%\times m_{solution}\Longrightarrow m_{NaOH}=\dfrac{25}{100}\times 0.250~g\iff\\\\\boxed{m_{NaOH}=0.0625~g}
Ulleksa [173]3 years ago
5 0

Answer : The mass of NaOH present in the solution is, 0.0625 grams

Explanation : Given,

Mass % = 25 %

Mass of solution = 0.250 g

Formula used :

Mass\%=\frac{\text{Mass of}NaOH}{\text{Mass of solution}}\times 100

Now put all the given values in this formula, we get the mass of NaOH.

25=\frac{\text{Mass of}NaOH}{0.250g}\times 100

\text{Mass of}NaOH=0.0625g

Therefore, the mass of NaOH present in the solution is, 0.0625 grams

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The theoretical yield of H₂S is 13.5 g.

The percent yield is 75.5 %.

<h3>What is the theoretical yield of H₂S from the reaction?</h3>

The equation of the reaction is given below:

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Moles of FeS reacting = mass/molar mass

Molar mass of FeS = 88 g/mol

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Actual yield of H₂S = 10.2 g

Percent yield = 10.2/13.5 * 100%

Percent yield = 75.5 %

In conclusion, the actual yield is less than the theoretical yield.

Learn more about percent yield at: brainly.com/question/8638404

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