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3 years ago

6

i need to kono why this app is so ....i get a add then i hav ea nohter add and there way to long. anyways 3 more weekds till sum

mer. have a good one

2 answers:

Vitek1552 [10]3 years ago

6 0

Answer: On the second add, the one that is about Brainly. Just get the cursor and skip to the end.

Explanation:

erastova [34]3 years ago

3 0

Answer:

same I hate all the frickin ads ;-;

you gave a good day too mate

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1) An unlabeled laboratory solution is found to contain a H+ ion concentration of 1 x 10-4

marishachu [46]

Answer:

C) 1 x 10-10 M

Explanation:

To solve this question we must use the equation:

Kw = [H+] [OH-]

<em>Where Kw is the equilibrium dissociation of water = 1x10-14</em>

<em>[H+] is the molar concentration of hydronium ion = 1x10-4M</em>

<em>[OH-] is the molar concentration of hydroxyl ion</em>

<em />

Replacing:

1x10-14= 1x10-4 [OH-]

<em>[OH-] = 1x10-14 / 1x10-4M</em>

<em>[OH-] = 1x10-10 M</em>

Right option is:

<h3>C) 1 x 10-10 M </h3>

7 0

3 years ago

Plz help me ppl I don't understand

labwork [276]

The chart is about atomic structure: at the top, the left box is "nucleus" and the right is "electron cloud".

On the left, under nucleus, the two boxes are: "protons" on the right and "neutrons" on the left. Under proton is elements which is given and under neutrons, it is "isotopes".

On the right, under electron cloud, the next box is "electrons" and then the lower box is "ions".

7 0

3 years ago

Read 2 more answers

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

3 0

3 years ago

The atomic number of an element that has 9 protons 9 electrons and 10 neutrons is?

natali 33 [55]

Answer:

nor its just

Explanation:

9 i need answer to be longer so im typing this out

7 0

3 years ago

A nurse practitioner prepares an injection of promethazine, an antihistamine used to treat allergic rhinitis. If the stock bottl

kherson [118]

The correct answer is 0.44ml

For information, promethazine is a neuroleptic antihistamine inhibitor of H1 receptors of the phenothiazine family. It is a medicine used in the treatment of allergy (like rhinitis) and transient insomnia.

To respond to this exercise, it is necessary to cross-multiply.

In the antihistamine bottle solution:

25 mg corresponds to 1 ml

11 mg corresponds to: 11/25 = 0.44 ml of the solution.

This 0.44ml is taken from the bottle and put to the syringe.

5 0

3 years ago