A fluid of density 1400 kg/m^3 and viscosity of 0.9 kg/m.s flows through an 80 mm diameter pipe with a velocity of 5 m/s. What t
1 answer:
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Solution :
Given :
k = 0.5 per day
Volume, V
Now, input rate = output rate + KCV ------------- (1)
Input rate
The output rate
= ( 40 + 0.5 ) x C x 1000
Decay rate = KCV
∴
= 1.16 C mg/s
Substituting all values in (1)
C = 4.93 mg/L
Answer:
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
Explanation:
Given data;
Let,
critical stress required for initiating crack propagation Cc = 112MPa
plain strain fracture toughness = 27.0MPa
surface length of the crack = a
dimensionless parameter = Y.
Half length of the internal crack, a = length of surface crack/2 = 8.8/2 = 4.4mm = 4.4*10-³m
Also for 6.2mm length of surface crack;
Half length of the internal crack = length of surface crack/2 = 6.2/2 = 3.1mm = 3.1*10-³m
The dimensionless parameter
Cc = Kic/(Y*√pia*a)
Y = Kic/(Cc*√pia*a)
Y = 27/(112*√pia*4.4*10-³)
Y = 2.05
Now,
Cc = Kic/(Y*√pia*a)
Cc = 27/(2.05*√pia*3.1*10-³)
Cc = 135.78MPa
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
For more understanding, I have provided an attachment to the solution.
Answer:
Input area=0.785x10^-4m^2
Output area=0.785x10^-6m^2
P1-p2=0.49x0.99v2
V1 =0.01v2
Explanation:
Please see attachment for step by step guide
