Answer:
hello your question lacks the required question attached below is the missing diagram
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
Explanation:
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
attached below is the detailed solution
Answer:
True.
Explanation: That's like putting salt in ur cereal instead of sugar
Answer:
a) the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air is 1065 kJ/min
Explanation:
Given the data in the question;
[ Outdoor ] ← Q [ W ] Q ← [ House ]
Rate of heat removed from the house; Q = 750 kJ/min = ( 750 kJ/min × ( 1 kW / 60 kJ/min ) ) = 12.5 kW
Net-work input; W = 5.25 kW
a) The coefficient of performance of the air conditioner; COP.
COP = Q / W
we substitute
COP = 12.5 kW / 5.25 kW
COP = 2.38
Therefore, the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air.
Q = Q + W
we substitute
Q = 12.5 kW + 5.25 kW
Q = 17.75 kW
Q = ( 17.75 × 60 ) kJ/min
Q = 1065 kJ/min
Therefore, the rate of heat transfer to the outside air is 1065 kJ/min
Answer: Safety boots are shoes made with a protective reinforcement at the front making them quite durable
Hoped I helped!