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andriy [413]
3 years ago
9

Find four consecutive integers with the sum of 54

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

54/4 = 13.5

 take the 2 whole numbers below 13.5 and the 2 whole numbers above 13.5

12 + 13 + 14 + 15 = 54

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A circle has an infinite amount of symmetry

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(x+3)(x-5)= in standard form
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x^2-2x-15

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<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a
yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0
3 years ago
Kevin has a spinner that has 10 equal sections and 2 sections of each color—red, blue, green, yellow, and purple. Kevin spins th
elena-s [515]
Hello!

You add the amount of sections have red or purple

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Put this over the amount of sections

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Multiply this by the amount of times he spins the spinner

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8 0
4 years ago
Can Someone help with this​
lesya [120]

Answer:

x        y

-2      5

-1 .      1

3 .       1

-1        -2

Step-by-step explanation:

in 1 just put in

x        y

-2      5

-1 .      1

3 .       1

-1        -2

5 0
3 years ago
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