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bija089 [108]
3 years ago
13

When a pendulum is swinging, the velocity is highest at which point?

Physics
2 answers:
strojnjashka [21]3 years ago
7 0
<h2>Answer:</h2>

<u>The velocity is highest </u><u>at the center, when the bob is hanging straight down </u>

<h2>Explanation:</h2>

As the pendulum swings to its highest position, its kinetic energy decreases to 0 on both right and left sides. If we tie a string to an object and let it swing back and forth, we will see that object’s velocity is 0 m/s at the highest points on the left and right sides and it is highest at at the center, when the bob is hanging straight down due to gravitational pull and the stored potential energy.

balu736 [363]3 years ago
4 0

Answer:

The velocity is highest at the lowest point of the trajectory

Explanation:

We can answer the question by applying the law of conservation of energy. In fact, neglecting friction and air resistance, the mechanical energy of the pendulum is constant during the motion:

E=K+U=const.

where:

K=\frac{1}{2}mv^2 is the kinetic energy, with m being the mass of the pendulum and v the velocity

U=mgh is the potential energy, with g being the acceleration due to gravity and h the heigth of the pendulum with respect to the lowest position

Since E must remain constant, we see that when K is maximum, U is minimum, and viceversa. This also means that when the velocity (v) is maximum, then the height (h) is minimum, so the pendulum must be at its lowest point.

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marshall27 [118]

Answer:

A

Explanation:

if he goes to the west, the east is opposite so 100-30

7 0
3 years ago
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What are the dimensions of potential energy?​
Pachacha [2.7K]

Potential Energy (P.E) = Mass x

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Potential energy= M1L2T-2.

5 0
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2
timama [110]

Answer:

A

Explanation:

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Could someone please help me with this question?​
Elenna [48]
1 because the the mid night summer is dark
3 0
3 years ago
A pipe is open at both ends. The pipe has resonant frequencies of 528 Hz and 660HZ (among others).
yawa3891 [41]

To develop this problem it is necessary to apply the oscillation frequency-related concepts specifically in string or pipe close at both ends or open at both ends.

By definition the oscillation frequency is defined as

f = n\frac{v}{2L}

Where

v = speed of sound

L = Length of the pipe

n = any integer which represent the number of repetition of the spectrum (n)1,2,3...)(Number of harmonic)

Re-arrange to find L,

f = n\frac{v}{2L}\\L = \frac{nv}{2f}

The radius between the two frequencies would be 4 to 5,

\frac{528Hz}{660Hz}= \frac{4}{5}

4:5

Therefore the frequencies are in the ratio of natural numbers.  That is

4f = 528\\f = \frac{528}{4}\\f = 132Hz

Here f represents the fundamental frequency.

Now using the expression to calculate the Length we have

L = \frac{nv}{2f}\\L = \frac{(1)343m/s}{2(132)}\\L = 1.29m

Therefore the length of the pipe is 1.3m

For the second harmonic n=2, then

L = \frac{nv}{2f}\\L = \frac{(2)343m/s}{2(132)}\\L = 2.59m

Therefore the length of the pipe in the second harmonic is 2.6m

7 0
3 years ago
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