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bija089 [108]
2 years ago
13

When a pendulum is swinging, the velocity is highest at which point?

Physics
2 answers:
strojnjashka [21]2 years ago
7 0
<h2>Answer:</h2>

<u>The velocity is highest </u><u>at the center, when the bob is hanging straight down </u>

<h2>Explanation:</h2>

As the pendulum swings to its highest position, its kinetic energy decreases to 0 on both right and left sides. If we tie a string to an object and let it swing back and forth, we will see that object’s velocity is 0 m/s at the highest points on the left and right sides and it is highest at at the center, when the bob is hanging straight down due to gravitational pull and the stored potential energy.

balu736 [363]2 years ago
4 0

Answer:

The velocity is highest at the lowest point of the trajectory

Explanation:

We can answer the question by applying the law of conservation of energy. In fact, neglecting friction and air resistance, the mechanical energy of the pendulum is constant during the motion:

E=K+U=const.

where:

K=\frac{1}{2}mv^2 is the kinetic energy, with m being the mass of the pendulum and v the velocity

U=mgh is the potential energy, with g being the acceleration due to gravity and h the heigth of the pendulum with respect to the lowest position

Since E must remain constant, we see that when K is maximum, U is minimum, and viceversa. This also means that when the velocity (v) is maximum, then the height (h) is minimum, so the pendulum must be at its lowest point.

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What type of friction occurs when you are trying to move an object, but the object isnt moving?
Tasya [4]

the answer is static friction


7 0
3 years ago
A rectangular copper strip 1.5cm wide and 0.10cn thick carries a current of 5.0A. Find the Hall voltage for a 1.2T magnetic fiel
Scrat [10]

Answer:

4.4345× 10^-7V

Explanation:

The computation of the half voltage for a 1.2T magnetic field applied is shown below

The volume of one mole of copper is

v = m ÷p

= 63.5 ÷ 8.92

= 7.12cm

Now the density of free electrons in copper is

n = Na ÷ V

= 6.02 × 10^23 ÷ 7.12

= 8.456× 10^28/m^3

Now the half voltage is

= IB ÷ nqt

= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)

= 4.4345× 10^-7V

7 0
2 years ago
A red laser from a physics lab is marked as producing 632.8 nm light. When light from this laser falls on two closely spaced sli
goblinko [34]

Given Information:  

Wavelength of the red laser = λr = 632.8 nm

Distance between bright fringes due to red laser = yr = 5 mm

Distance between bright fringes due to laser pointer = yp = 5.14 mm

Required Information:  

Wavelength of the laser pointer = λp = ?

Answer:

Wavelength of the laser pointer = λp = ?

Explanation:

The wavelength of the monochromatic light can be found using young's double slits formula,

y = Dλ/d  

y/λ = D/d

Where

λ is the wavelength

y is the distance between bright fringes.

d is the double slit separation distance

D is the distance from the slits to the screen

For the red laser,

yr/λr = D/d

For the laser pointer,

yp/λp = D/d

Equating both equations yields,

yr/λr = yp/λp

Re-arrange for λp

λp = yp*λr/yr

λp =  (5*632.8)/5.14

λp = 615.56 nm

Therefore, the wavelength of the small laser pointer is 615.56 nm.

3 0
3 years ago
What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
pentagon [3]

Answer:

\tau_a = F a sin \theta

Explanation:

The torque of a force is given by:

\tau = F d sin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the centre of rotation of the system

\theta is the angle between the direction of the force and d

In this problem, we have:

F, the force

a, the distance of application of the force from the centre (0,0)

\theta, the angle between the direction of the force and a

Therefore, the torque is

\tau_a = F a sin \theta

5 0
3 years ago
Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
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