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Dmitry_Shevchenko [17]
3 years ago
6

A toboggan is sliding down an icy slope. As it goes down, _________ does work on the toboggan and ends up converting __________

energy to _________ energy.
Physics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

1. weight

2. <u>gravitational potential</u> energy to <u>kinetic</u> energy.

Explanation:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

work done by toboggan = weight × distance

W = mg and the distance is down the icy slope

By using law of conservation of energy, energy can neither be created nor destroyed, but can be conserve from one form to another in a closed system.

Toboggan converts gravitational potential energy (mgh) to kinetic energy(¹/₂mv²)

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a large truck has a mass of 20000kg. it is traveling at 28m/s along a staright road . calculate the kinetic energy ​
Semmy [17]

Answer:

The answer is

<h2>7,840,000 J</h2>

Explanation:

The kinetic energy KE of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

where

m is the mass

v is the velocity

From the question

m = 20000kg

v = 28 m/s

It's kinetic energy is

KE =  \frac{1}{2}  \times 20000 \times  {28}^{2}  \\  = 10000 \times 784

We have the final answer as

<h3>7,840,000 J</h3>

Hope this helps you

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ankoles [38]

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2 years ago
A cue ball with mass 170g hits a stationary number 8 ball, which has mass 160g. The cue ball
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Answer:

0.49 m/s

Explanation:

The law of conservation of linear momentum states that the sum of momentum in a system before and after collision are same. Momentum is a product of mass and velocity of an object hence in this case

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Where m represent mass, u and v represent the initial and final velocities respectively, subscripts c and 8 represent cue ball and number 8 ball respectively.

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170u_c+160*0=170*0.2+170*0.3\\u_c\approx 0.49 m/s

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