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Dmitry_Shevchenko [17]

3 years ago

6

A toboggan is sliding down an icy slope. As it goes down, _ does work on the toboggan and ends up converting __

energy to _________ energy.

1 answer:

MariettaO [177]3 years ago

3 0

Answer:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

1. weight

2. <u>gravitational potential</u> energy to <u>kinetic</u> energy.

Explanation:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

work done by toboggan = weight × distance

W = mg and the distance is down the icy slope

By using law of conservation of energy, energy can neither be created nor destroyed, but can be conserve from one form to another in a closed system.

Toboggan converts gravitational potential energy (mgh) to kinetic energy(¹/₂mv²)

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vaieri [72.5K]

D.sound insulators prevent from being transmitted better than elastic solids

Explanation:

The correct option from the given choices is that, sound insulators prevent sound from being transmitted better than elastic solids.

Sound is a form of wave that transmits energy from one point to another.

This wave form is a longitudinal wave in nature.

During the propagation of sound, it requires a material medium to move.

Sound insulators are special materials designed not to transmit sound energy.

Such materials cuts off sound. They are better than elastic solids in preventing sound transmission.

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8 0

3 years ago

Help please I’ll mark as brainliest

IceJOKER [234]

Sorry for the messy handwriting but this is what I got

5 0

2 years ago

Explain the differences in structure and use for life between oxygen gas in the atmosphere and ozone.

navik [9.2K]

Answer:

Most of the oxygen in the atmosphere is in the form of O2, which means it is made up of molecules containing two oxygen atoms. Ozone, however is O3, which means it is made up of molecules containing three oxygen atoms. O2 is what we breath, and what plants release from photosynthesis. Ozone occurs naturally high in the stratosphere, where it absorbs ultraviolet light, protecting us here on the surface from skin cancer. Ozone can also occur closer to the surface of the earth as a pollutant. It is formed from reactions with O2 and chemicals emitted from factories and cars. It comes in the form of smog.

So in general:

Oxygen (O2): Essential to human life

Ozone (O3) in the stratosphere: essential to protecting life on earth

Ozone (O3) on the surface of the earth: toxic to human life, caused by pollution

5 0

2 years ago

A rock of mass m is thrown straight up into the air with initial speed |v0 | and initial position y = 0 and it rises up to a max

REY [17]

Answer:

Explanation:

Case 1:

mass = m

initial velocity = vo

final velocity = 0

height = y

Use third equation of motion

v² = u² - 2as

0 = vo² - 2 g y

y = vo² / 2g ... (1)

Case 2:

mass = 2m

initial velocity = 2vo

final velocity = 0

height = y '

Use third equation of motion

v² = u² - 2as

0 = 4vo² - 2 g y'

y ' = 4vo² / 2g

y' = 4 y

Thus, the second rock reaches the 4 times the distance traveled by the first rock.

7 0

2 years ago

uniform disk with mass 40.0 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is station

Alex787 [66]

Answer:

The magnitude of the tangential velocity is $v= 0.868 m/s$

The magnitude of the resultant acceleration at that point is $a = 4.057 m/s^2$

Explanation:

From the question we are told that

The mass of the uniform disk is $m_d = 40.0kg$

The radius of the uniform disk is $R_d = 0.200m$

The force applied on the disk is $F_d = 30.0N$

Generally the angular speed i mathematically represented as

$w = \sqrt{2 \alpha \theta}$

Where $\theta$ is the angular displacement given from the question as

$\theta = 0.2000 rev = 0.2000 rev * \frac{2 \pi \ rad }{1 rev}$

$=1.257\ rad$

$\alpha$ is the angular acceleration which is mathematically represented as

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

The moment of inertial is mathematically represented as

$I = \frac{1}{2} m_dR^2_d$

Substituting values

$I = 0.5 * 40 * 0.200^2$

$= 0.8kg \cdot m^2$

Considering the equation for angular acceleration

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

Substituting values

$\alph$ $\alpha = \frac{(30.0)(0.200)}{0.8}$

$= 7.5 rad/s^2$

Considering the equation for angular velocity

$w = \sqrt{2 \alpha \theta}$

Substituting values

$w =\sqrt{2 * (7.5) * 1.257}$

$= 4.34 \ rad/s$

The tangential velocity of a given point on the rim is mathematically represented as

$v = R_d w$

Substituting values

$= (0.200)(4.34)$

$v= 0.868 m/s$

The radial acceleration at hat point is mathematically represented as

$\alpha_r = \frac{v^2}{R}$

$= \frac{0.868^2}{0.200^2}$

$= 3.7699 \ m/s^2$

The tangential acceleration at that point is mathematically represented as

$\alpha _t = R \alpha$

Substituting values

$\alpha _t = (0.200) (7.5)$

$= 1.5 m/s^2$

The magnitude of resultant acceleration at that point is

$a = \sqrt{\alpha_r ^2+ \alpha_t^2 }$

Substituting values

$a = \sqrt{(3.7699)^2 + (1.5)^2}$

$a = 4.057 m/s^2$

7 0

3 years ago