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Dmitry_Shevchenko [17]
3 years ago
6

A toboggan is sliding down an icy slope. As it goes down, _________ does work on the toboggan and ends up converting __________

energy to _________ energy.
Physics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

1. weight

2. <u>gravitational potential</u> energy to <u>kinetic</u> energy.

Explanation:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

work done by toboggan = weight × distance

W = mg and the distance is down the icy slope

By using law of conservation of energy, energy can neither be created nor destroyed, but can be conserve from one form to another in a closed system.

Toboggan converts gravitational potential energy (mgh) to kinetic energy(¹/₂mv²)

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Answer:

19.3m/s

Explanation:

Use third equation of motion

v^2-u^2=2gh

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insert values to get answer

v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s

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3 years ago
The deliberate radiation of electromagnetic (EM) energy to degrade or neutralize the radio frequency long-haul supervisory contr
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Answer:

Best explains Jamming

Explanation:

<em>The deliberate radiation of electromagnetic (EM) energy to degrade or neutralize the radio frequency long-haul supervisory control and data acquisition (SCADA) communications links, best explains what?</em>

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6 0
3 years ago
it takes 90 j of work to stretch a spring 0.2 m from its equilibrium position. How muc work is needed to stretch it an additiona
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Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring from the equilibrium position

In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

k=\frac{2E}{x^2}=\frac{2(90)}{(0.2)^2}=4500 N/m

Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

x = 0.2 + 0.4 = 0.6 m

Substituting,

E'=\frac{1}{2}kx^2=\frac{1}{2}(4500)(0.6)^2=810 J

Therefore, the additional work needed is

\Delta E=E'-E=810-90=720 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
What is the net work on the block?
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Answer:

A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size

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Answer:

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b) F_{fr}= \mu mg = F_{pull}, then \mu = \frac{F_{pull}}{mg} = 0.0557.

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