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Dmitry_Shevchenko [17]
4 years ago
6

A toboggan is sliding down an icy slope. As it goes down, _________ does work on the toboggan and ends up converting __________

energy to _________ energy.
Physics
1 answer:
MariettaO [177]4 years ago
3 0

Answer:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

1. weight

2. <u>gravitational potential</u> energy to <u>kinetic</u> energy.

Explanation:

As it goes down, <u>weight</u> does work on the toboggan and it ends up converting <u>gravitational potential</u> energy to <u>kinetic</u> energy.

work done by toboggan = weight × distance

W = mg and the distance is down the icy slope

By using law of conservation of energy, energy can neither be created nor destroyed, but can be conserve from one form to another in a closed system.

Toboggan converts gravitational potential energy (mgh) to kinetic energy(¹/₂mv²)

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A cannon is fired from a castle wall at some unknown height above the ground. The cannonball leaves the cannon with speed 30.0m/
Sauron [17]

Answer:

Part a)

t = 3.85 s

Part b)

h = 72.67 m

Part C)

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = -22.77 m/s

Explanation:

Part a)

Horizontal speed of the cannon

v = 30.0 m/s

angle of projection

\theta = 30^o

now we have

horizontal speed = v_x = vcos30 = 30 cos30 =25.98 m/s

vertical speed = v_y = vsin30 = 30 sin30 = 15 m/s

now the time taken by it to cover the distance 100 m from the wall

x = v_x t

100 = 25.98 t

t = 3.85 s

Part b)

Since it hits the ground in the same time

so the height of the castle is given as

h = \frac{1}{2}gt^2

h = \frac{1}{2}(9.81)(3.85^2)

h = 72.67 m

Part C)

At highest point of the projection

the vertical component of the velocity will become zero

so we will have

v_x = 25.98 m/s

v_y = 0

Part d)

In horizontal direction velocity will remain constant

so we have

v_x = 30 cos30 = 25.98 m/s

in vertical direction we have

v_y = v_i + at

v_y = 15 - 9.81(3.85)

v_y = -22.77 m/s

Part e)

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3 years ago
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irina [24]

Answer:

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2) T = 4.5 s

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Explanation:

We can use the equation

T = 2π√(L/g)

1) T = 2π√(5m/9.81 m/s²) = 4.5 s

2) T = 2π√(L/g)

T = 2π√(5m/9.81 m/s²) = 4.5 s

3) v = √(2gR)

v = √(2(9.81 m/s²)(5m))

v = 9.9 m/s

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yan [13]

Answer:

Prob. D

Explanation:

I am also a Visual Learner.

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Answer:

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