1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
konstantin123 [22]
3 years ago
14

PLS ANSWER ASAP!!

Physics
1 answer:
koban [17]3 years ago
4 0

Answer:

<em>The closest choice to the answer is 34.0 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion experienced by an object that is launched near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the Range or maximum horizontal distance traveled by the object is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The football is kicked at an angle of 30° with an initial velocity of 20 m/s. Replacing those values:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ)}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ)}{9.8}}=35.35\ m

The closest choice to the answer is 34.0 m

You might be interested in
Which of the following is a vector quantity?
djverab [1.8K]

Vector quantity is defined by direction as well as magnitude both

so now lets discuss all option

1) distance = it is total path length between two points so there is no direction needed in it so it is scalar

2) Speed = it is ratio of total distance covered and total time, so it also do not require any direction.

<em>3)velocity = it is ratio of displacement and time, and displacement is always given with direction so velocity is a vector quantity</em>

4) time = time is the measurement of the interval of two events and we do not require any direction in it so its a scalar quantity.

4 0
3 years ago
What is the marble's range if it is fired horizontally from 1.6 m above the ground?
cupoosta [38]

Answer:

The answer is 6.40 meters.

Explanation:

The speed v = √(2gh)

v = √( 2×9.8×6.4) = 11.2 m/s

After, finding the time it takes to hit the ground from a height of 1.6 meters.

time = √(2H÷g)

time = √(2×1.6÷9.8)

time = 0.5714 seconds.

Horizontal distance is speed × time = 11.2 × 0.5714 = 6.40 meters.

5 0
3 years ago
State advantages of ultrasonic sound in determining the depth of the ocean ​
agasfer [191]

Answer:

It has <u>greater accuracy than other nondestructive methods in determining the depth of internal flaws and the thickness of parts with parallel surfaces.</u>

Explanation:

Hope this helps you!

5 0
2 years ago
Which of the following is not a characteristic of a electrical potential energy?
spin [16.1K]
It's a form of mechanical energy
8 0
3 years ago
Read 2 more answers
A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha
Slav-nsk [51]

Jsdjdjjjdjdjd

Explanation:Sjsjsjsmjsjddhdmddjdidujddjdujddmjsisisi daddy dickkkdududjdjsjsusjsususuksuckmpormmjsjdjsjxjxxjjjsusjhs

5 0
3 years ago
Other questions:
  • What is the closest star that could go supernova?
    11·1 answer
  • PLEASE HELP!!!
    5·1 answer
  • Total amount of kinetic and potential energy in a system ​
    11·1 answer
  • Explain how Rutherfords' gold foil experiment explains how this experiment confirms the nuclear model of the atom and the idea t
    15·1 answer
  • Which instrument changes kinetic energy into electrical energy?
    8·1 answer
  • What must be the reaction force when someone hits a tree with an axe?
    12·1 answer
  • An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos
    7·1 answer
  • Correct displacement 4km south,2 km north, 5km south, and 5 km north
    10·1 answer
  • consider the hypothetical observation irregular galaxies outside the local group are moving toward us. from part a, this observa
    5·1 answer
  • Part 1
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!