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konstantin123 [22]
3 years ago
14

PLS ANSWER ASAP!!

Physics
1 answer:
koban [17]3 years ago
4 0

Answer:

<em>The closest choice to the answer is 34.0 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion experienced by an object that is launched near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the Range or maximum horizontal distance traveled by the object is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The football is kicked at an angle of 30° with an initial velocity of 20 m/s. Replacing those values:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ)}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ)}{9.8}}=35.35\ m

The closest choice to the answer is 34.0 m

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Magnetic induction is used for what?
DochEvi [55]
For radio broadcasting, in electricity meters, in any generator. 
4 0
3 years ago
Can you please help me
konstantin123 [22]

Answer:

I dont know sorryyyyyyy

4 0
3 years ago
A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n
Sholpan [36]

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

5 0
3 years ago
Answer the question based on this waveform.
Nuetrik [128]

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.

6 0
3 years ago
How long does it take light to travel 850 km in a vacuum? Answer in ms.(Express your answer to two significant figures.)
poizon [28]

Answer:

0.002833 sec

Explanation:

Speed of light in vacuum is 3\times 10^{8}m/sec

Given distance = 850 km = 850×1000=850000 m

We have to calculate the time that light take to travel the distance 850 km

Time T=\frac{distance }{speed}=\frac{850000}{3\times 10^8}=2.833\times 10^{-3}sec

So the time taken by light to travel 850 km is 0.002833 sec

5 0
3 years ago
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