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NISA [10]
3 years ago
10

Why does a heater having low resistance heating coils get heated more?​

Physics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer: If you use a very small resistance AND the circuit design is such that the voltage drop is across the resistance of the heating-wire-circuit, [nothing else in the circuit is limiting current flow] you will get more heating. That's what we have in a heat anticipator internal-nichrome-wire-heater device.

Explanation:

algol [13]3 years ago
3 0

Answer:

Explanation:

That electrical energy will be dissipated in the form of heat, heating up the wire in the process. This heating is called Joule heating (James Prescott Joule) or ohmic heating or resistive heating. Which tells us that lower resistance (R) will produce higher current. Therefore lower resistance produces more heat.

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When the child is moving, he/she has kinetic energy. For just a brief second before they move the other way, the child is not moving, but they have gravitational potential energy.

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which instrument is best suited for measuring the dimensions of a shoebox? a)a triple-beam balance b)a volumetric flask c)a rule
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3 years ago
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Explanation:

7 0
3 years ago
When fireworks explode, sound and light are produced. These are examples of
ki77a [65]

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Explanation:

Answers to the rest:

1. B) macroscopic outputs.

2.A) a microscopic change creating a macroscopic output

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6 0
2 years ago
A fluid, with a density of rho = 1165 kg/m3, flows in a horizontal pipe. In one segment of the pipe the flow speed is v1 = 4.53
Elza [17]

Answer:

The pressure difference between two pipe is 1.01 \times 10^{4} Pa

Explanation:

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Speed in one pipe v_{1} = 4.53 \frac{m}{s}

Speed in second pipe v_{2} = 1.77 \frac{m}{s}

According to the bernoulli equation,

The pressure difference is given by,

     P = \frac{1}{2} \rho v^{2}

P_{2} - P_{1} = \frac{1}{2}  \rho (v_{1}^{2}  - v_{2}^{2}  )

P_{2} - P_{1} = \frac{1}{2} \times 1165 \times[ (4.53)^{2}- (1.77)^{2}]

P_{2} - P_{1} = 10128.51

P_{2} - P_{1} = 1.01 \times 10^{4} Pa

Therefore, the pressure difference between two pipe is 1.01 \times 10^{4} Pa

6 0
3 years ago
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