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NISA [10]
3 years ago
10

Why does a heater having low resistance heating coils get heated more?​

Physics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer: If you use a very small resistance AND the circuit design is such that the voltage drop is across the resistance of the heating-wire-circuit, [nothing else in the circuit is limiting current flow] you will get more heating. That's what we have in a heat anticipator internal-nichrome-wire-heater device.

Explanation:

algol [13]3 years ago
3 0

Answer:

Explanation:

That electrical energy will be dissipated in the form of heat, heating up the wire in the process. This heating is called Joule heating (James Prescott Joule) or ohmic heating or resistive heating. Which tells us that lower resistance (R) will produce higher current. Therefore lower resistance produces more heat.

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Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is
igor_vitrenko [27]

Answer:

240 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).

The expression for resistance power and voltage is give as,

P = V²/R.......................... Equation 1

Where P = Power, V = Voltage, R = Resistance

Making R the subject of the equation,

R = V²/P.................... Equation 2

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0
3 years ago
What do the magnets in a computer hard drive and in the strip on a credit
Sonja [21]

Answer:

they store information

Explanation:

Information are encoded on the magnetic part of a hard drive and the strip of a credit card.

  • On the drive, series of magnetic fields are used to encode information.
  • The data is stored in form of zeros and ones.
  • A credit card has a magnetic strip where information is encoded.
  • The stripe provides a readability function for electronic devices.
5 0
3 years ago
How much heat is needed to raise the temperature of 2 kg of copper from 20º to 30ºC. The specific heat of copper is 390 J/kgºC.
ryzh [129]

Answer:

7800 J

Explanation:

Heat needed = mass of copper x specific heat of copper x change in temperature  

Change in temperature = 30ºC - 20ºC = 10ºC

Specific heat of copper = 390 J/kgºC

Mass of copper = 2 Kg

Substituting the given values in above equation, we get –  

Heat needed = 2 Kg x 390 J/kgºC x 10ºC

= 7800 J

3 0
4 years ago
How To do this question
777dan777 [17]
Since it is given that their particles have a large difference in size, we can conclude that the particles of small size get embedded into the space between the particles of large size. Thus it doesn't increased it volume as it should have.
6 0
3 years ago
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