Initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity

Physics

1 answer:

stiks02 [169]3 years ago

8 0

Answer:

<em>The final velocity is 20 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

$v_f=v_o+at$

The provided data is: vo=10 m/s, $a=5\ m/s^2$ , t=2 s. The final velocity is:

$v_f=10~m/s+5\ m/s^2\cdot 2\ s$

$v_f=20\ m/s$

The final velocity is 20 m/s.

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An object is falling from a height of 7.5 meters. At what height will it’s velocity be 7 meters/second?

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One of the equations of gravity is this:
${v}^{2} = {u}^{2} + 2gh$
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u = initial velocity which is 0 for objects falling from a height
g = acceleration due to gravity and it is approximately 10m/s^2. It's a constant so pretty much remember this number. It's positive since the work being done is caused by gravity (in other words, it's falling down). It can also be negative if the work being down is against gravity (in other words, it's going up)
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Substitute for the values and you should have something like this
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$h = \frac{49}{20}$
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