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omeli [17]
3 years ago
9

A 5.5kg mass is pushed with a force of 31N across a table having μk of 0.350. Find how fast it will accelerate, taking friction

into consideration.

Physics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

3.66m/s^2

Explanation:

First, we need to find the friction which is F=u*N.

After that, find the resultant force by substarcting the friction from the forward force.

Lastly,using the formula F=ma, substitute in the known values of F and m to find a

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Compared to a stationary galaxy, light from a galaxy that is moving away from earth will appear _____.
Vlad1618 [11]
"B" When an object moves away from us, the light is shifted to the red end of the spectrum, as its wavelengths get longer.
3 0
3 years ago
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Rama's weight is 4okg: She is carrying a load of 20kg up to a height of 20 meters.what work does she do?Also mention its type of
Maslowich

Answer:

rama is doing

Explanation:

work done=f×d×g

=60×20×9.8

=11760j

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8 0
3 years ago
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

8 0
3 years ago
Can you help me on this fast just the second one
Mariulka [41]
4. E
5. D
6. F

Hope this helps
3 0
4 years ago
a ball was projected in such a way that it attained the maximum horizontal distance with a velocity of 20m/s calculate the verti
Eduardwww [97]

Answer:

80m

Explanation:

u=20,R=?,sin theta=1,g=10

R=u²sin2theta/g

R=20²x2/10

R=400x2=800/10

R=80m

7 0
3 years ago
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