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Gwar [14]
3 years ago
10

What is a prediction​

Physics
2 answers:
allochka39001 [22]3 years ago
7 0

Answer:a thing predicted; a forecast.

Explanation:

alexdok [17]3 years ago
4 0

Answer: To predict what happens before something does

Explanation:

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Calculate the change in length of a Pyrex glass dish (Coefficient of linear expansion for Pyrex is 3 x 10^-6 /C) that is 0.3 met
Readme [11.4K]

Answer:

0.000225 m

Explanation:

Coefficient of linear expansion = \alpha_L=3\times 10^{-6} /C

Length = 0.3 meters

ΔT = Change in temperature = 250 °C

Linear expansion

\frac{\Delta L}{L} = \alpha_L\Delta T\\\Rightarrow \Delta L=\alpha_L\Delta T\times L\\\Rightarrow \Delta L=3\times 10^{-6}\times 0.3\times 250=0.000225\ m

Change in length of the Pyrex glass dish is 0.000225 m.

3 0
3 years ago
If the mass of one of two particles is doubled and
UkoKoshka [18]

Answer: 4

Explanation:

5 0
2 years ago
Volcano has both useful and harmful effects give reason​
alina1380 [7]

Answer:

harmful effects

1. that will cause air pollution

2. that will destroy our earth

3 0
3 years ago
Read 2 more answers
Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t
Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v^2=v_0^2+2ax\\

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

    = 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

F_f=ma=(1490kg)(5.55m/s^2)=8271.15N

Furthermore, you use the relation between the friction force and the friction coefficient:

F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56

hence, the friction coefficient is 0.56

6 0
3 years ago
A 0.900-V potential difference is maintained across a 1.5m length of 2
Daniel [21]

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, A=0.6\ mm^2=6\times 10^{-7}\ m^2

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A

So, the current in the wire is 6.42 A.

3 0
3 years ago
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