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nekit [7.7K]
3 years ago
13

Albert Bandura’s theory, originally called social learning theory, is now referred to as __________, and it suggests cognitive p

rocesses play a role in influencing one’s personality.
Physics
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

social cognitive theory

Explanation:

Albert Bandura's theory, originally called social learning theory, is now referred to as <em><u>social cognitive theory, </u></em>and it suggests cognitive processes play a role in influencing one's personality.

Alborosie3 years ago
7 0

Answer:

D

Explanation:

Edge

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A positively charged light metal ball is suspended between two oppositely charged metal plates on an insulating thread as shown
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Answer:

The positive ball would go first to the negatively charged plate.

Explanation:

After which, it would hold a more negative charge. Due to the negative charge, it would travel towards the positive plate. Thereby, it would transfer negative electrons to the positive plate once more. In doing so, it would transfer positive protons to the negative plate. After which, it would hold more  negative electrons and be drawn towards the positive plate once more. The Process would continue until the once-positive and once-negative became neutral ( and were discharged.) Additionally, the ball hanging on the insulator thread would also be neutral and discharged.

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3 years ago
The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron
FrozenT [24]

Answer:

<em>Speed of the electron is 2.46 x 10^8 m/s</em>

<em></em>

Explanation:

momentum of the electron before relativistic effect = M_{0} V

where M_{0} is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = M_{0}/ \sqrt{1 - \beta ^{2}  }

where

\beta = V/c

c  is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> M_{0}V/ \sqrt{1 - \beta ^{2}  }

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75M_{0} V = M_{0}V/ \sqrt{1 - \beta ^{2}  }

the equation reduces to

1.75 = 1/ \sqrt{1 - \beta ^{2}  }

square both sides of the equation, we have

3.0625 = 1/(1 - \beta ^{2} )

3.0625 - 3.0625\beta ^{2} = 1

2.0625 = 3.0625\beta ^{2}

\beta ^{2} = 0.67

β = 0.819

substitute for  \beta = V/c

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = <em>2.46 x 10^8 m/s</em>

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3 years ago
Read 2 more answers
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